如何使用JmsTemplate进行手动确认并从Rabbitmq队列中删除消息
我在jmsTemplate中使用RabbitMq(带有JMS),我可以使用RabbitMq队列中的消息,但是它是自动确认的。
我有Search API,但找不到它。
如何设置手动确认。
在下面的代码中,当从队列中消费了消息时,我想用该消息调用Web服务,并取决于来自我的响应,我想从队列中删除该消息。我创建了一个项目,其中我正在使用侦听器,而另一个项目是通过调用从队列中读取消息
第一个项目:
package com.es.jms.listener;import javax.jms.ConnectionFactory;
import javax.jms.JMSException;
import javax.jms.Message;
import javax.jms.MessageListener;
import javax.jms.TextMessage;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.jms.listener.MessageListenerContainer;
import org.springframework.jms.listener.SimpleMessageListenerContainer;
import com.rabbitmq.jms.admin.RMQConnectionFactory;
@Configuration
public class RabbitMqMessageListener {
@Bean
public ConnectionFactory jmsConnectionFactory() {
RMQConnectionFactory connectionFactory = new RMQConnectionFactory();
connectionFactory.setUsername("Username");
connectionFactory.setPassword("Password");
connectionFactory.setVirtualHost("vhostname");
connectionFactory.setHost("hostname");
return connectionFactory;
}
@Bean
public MessageListener msgListener() {
return new MessageListener() {
public void onMessage(Message message) {
System.out.println(message.toString());
if (message instanceof TextMessage) {
try {
String msg = ((TextMessage) message).getText();
System.out.println("Received message: " + msg);
// call web service here and depends on web service
// response
// if 200 then delete msg from queue else keep msg in
// queue
} catch (JMSException ex) {
throw new RuntimeException(ex);
}
}
}
};
}
@Bean
public MessageListenerContainer messageListenerContainer() {
SimpleMessageListenerContainer container = new SimpleMessageListenerContainer();
container.setConnectionFactory(jmsConnectionFactory());
container.setDestinationName("test");
container.setMessageListener(msgListener());
return container;
}
}
第二项目:
package com.rabbitmq.jms.consumer.controller;import java.util.concurrent.ExecutionException;
import java.util.concurrent.TimeoutException;
import javax.jms.ConnectionFactory;
import org.json.JSONException;
import org.json.JSONObject;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.annotation.Bean;
import org.springframework.http.HttpStatus;
import org.springframework.http.ResponseEntity;
import org.springframework.jms.JmsException;
import org.springframework.jms.core.JmsTemplate;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.CrossOrigin;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import com.rabbitmq.jms.admin.RMQConnectionFactory;
import redis.clients.jedis.Jedis;
@Controller
public class ReceiverController {
@Autowired
JmsTemplate jmsTemplate;
@Bean
public ConnectionFactory jmsConnectionFactory() {
RMQConnectionFactory connectionFactory = new RMQConnectionFactory();
connectionFactory.setUsername("Username");
connectionFactory.setPassword("Password");
connectionFactory.setVirtualHost("vhostname");
connectionFactory.setHost("hostname");
return connectionFactory;
}
@CrossOrigin
@SuppressWarnings({ "unchecked", "rawtypes" })
@RequestMapping(method = RequestMethod.GET, value = "/getdata")
@ResponseBody
public ResponseEntity<String> fecthDataFromRedis()
throws JSONException, InterruptedException, JmsException, ExecutionException, TimeoutException {
System.out.println("in controller");
jmsTemplate.setReceiveTimeout(500L);
// jmsTemplate.
String message = (String) jmsTemplate.receiveAndConvert("test");
// call web service here and depends on web service
// response
// if 200 then delete msg from queue else keep msg in
// queue
System.out.println(message);
}
return new ResponseEntity(message , HttpStatus.OK);
}
}
我怎样才能做到这一点?
提前致谢。
回答:
您没有使用JmsTemplate
,而是使用SimpleMessageListenerContainer
来接收消息。
如果您 是 使用模板,你将不得不使用的execute
方法有SessionCallback
,因为必须确认其内接收消息的会话的范围内。
但是,使用SimpleMessageListenerContainer
,您只需将设置sessionAcknowledgeMode
为Session.CLIENT_ACKNOWLEDGE
。参见容器javadocs
…
/** * Message listener container that uses the plain JMS client API's
* {@code MessageConsumer.setMessageListener()} method to
* create concurrent MessageConsumers for the specified listeners.
*
* <p>This is the simplest form of a message listener container.
* It creates a fixed number of JMS Sessions to invoke the listener,
* not allowing for dynamic adaptation to runtime demands. Its main
* advantage is its low level of complexity and the minimum requirements
* on the JMS provider: Not even the ServerSessionPool facility is required.
*
* <p>See the {@link AbstractMessageListenerContainer} javadoc for details
* on acknowledge modes and transaction options. Note that this container
* exposes standard JMS behavior for the default "AUTO_ACKNOWLEDGE" mode:
* that is, automatic message acknowledgment after listener execution,
* with no redelivery in case of a user exception thrown but potential
* redelivery in case of the JVM dying during listener execution.
*
* <p>For a different style of MessageListener handling, through looped
* {@code MessageConsumer.receive()} calls that also allow for
* transactional reception of messages (registering them with XA transactions),
* see {@link DefaultMessageListenerContainer}.
...
使用时JmsTemplate
,您必须在会话范围内进行工作-这是…
首先,您必须在模板中启用客户端确认…
this.jmsTemplate.setSessionAcknowledgeMode(Session.CLIENT_ACKNOWLEDGE);
然后,将execute
方法与SessionCallback
…一起使用
Boolean result = this.jmsTemplate.execute(session -> { MessageConsumer consumer = session.createConsumer(
this.jmsTemplate.getDestinationResolver().resolveDestinationName(session, "bar", false));
String result = null;
try {
Message received = consumer.receive(5000);
if (received != null) {
result = (String) this.jmsTemplate.getMessageConverter().fromMessage(received);
// Do some stuff here.
received.acknowledge();
return true;
}
}
catch (Exception e) {
return false;
}
finally {
consumer.close();
}
}, true);
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