MySQL中的排名函数

我需要找出客户的等级。在这里,我为我的需求添加了相应的ANSI标准SQL查询。请帮助我将其转换为MySQL。

SELECT RANK() OVER (PARTITION BY Gender ORDER BY Age) AS [Partition by Gender], 

FirstName,

Age,

Gender

FROM Person

有什么功能可以找出MySQL的排名吗?

回答:

一种选择是使用排名变量,例如:

SELECT    first_name,

age,

gender,

@curRank := @curRank + 1 AS rank

FROM person p, (SELECT @curRank := 0) r

ORDER BY age;

(SELECT @curRank := 0)部分允许变量初始化,而无需单独的SET命令。

测试用例:

CREATE TABLE person (id int, first_name varchar(20), age int, gender char(1));

INSERT INTO person VALUES (1, 'Bob', 25, 'M');

INSERT INTO person VALUES (2, 'Jane', 20, 'F');

INSERT INTO person VALUES (3, 'Jack', 30, 'M');

INSERT INTO person VALUES (4, 'Bill', 32, 'M');

INSERT INTO person VALUES (5, 'Nick', 22, 'M');

INSERT INTO person VALUES (6, 'Kathy', 18, 'F');

INSERT INTO person VALUES (7, 'Steve', 36, 'M');

INSERT INTO person VALUES (8, 'Anne', 25, 'F');

结果:

+------------+------+--------+------+

| first_name | age | gender | rank |

+------------+------+--------+------+

| Kathy | 18 | F | 1 |

| Jane | 20 | F | 2 |

| Nick | 22 | M | 3 |

| Bob | 25 | M | 4 |

| Anne | 25 | F | 5 |

| Jack | 30 | M | 6 |

| Bill | 32 | M | 7 |

| Steve | 36 | M | 8 |

+------------+------+--------+------+

8 rows in set (0.02 sec)

以上是 MySQL中的排名函数 的全部内容, 来源链接: utcz.com/qa/431547.html

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