将嵌套的Java对象转换为Jackson JSON

有人可以提供一个示例或参考,该示例或参考提供一种使用Jackson库将嵌套JAVA对象转换为JSON输出的方法的方法。我没有转换平面JAVA对象的问题。但是,JSON库显示嵌套的对象名称和类型,而不是其子对象。我几乎可以利用此处提供的相同代码http://www.mkyong.com/java/jackson-2-convert-

java-object-to-from-json/。因此,我没有附加任何代码示例。

例如

{

"fname": null,

"lname": null,

"addr": null

}

{

"name":null,

"lname":null,

"addr":{

street:"mull",

"city":null,

"zip":0

}

}

import address;

public class id implements Serializable {

public String fname;

public String lname;

public address addr;

}

public class address implements Serializable {

public String street;

public String city;

public int zip;

}

回答:

创建一个类地址。

public class Address {

private String street;

private String city;

private int zip;

public String getStreet() {

return street;

}

public void setStreet(String street) {

this.street = street;

}

public String getCity() {

return city;

}

public void setCity(String city) {

this.city = city;

}

public int getZip() {

return zip;

}

public void setZip(int zip) {

this.zip = zip;

}

}

创建一个类别ID。

 public class Id {

private String fname;

private String lname;

private Address addr;

public String getFname() {

return fname;

}

public void setFname(String fname) {

this.fname = fname;

}

public String getLname() {

return lname;

}

public void setLname(String lname) {

this.lname = lname;

}

public Address getAddr() {

return addr;

}

public void setAddr(Address addr) {

this.addr = addr;

}

}

主要方法:

import com.fasterxml.jackson.core.JsonProcessingException;

import com.fasterxml.jackson.databind.ObjectMapper;

public class Test {

public static void main(String[] args) {

Address addressObj = new Address();

addressObj.setCity("Chicago");

addressObj.setStreet("Some Street");

addressObj.setZip(12345);

Id idObj = new Id();

idObj.setAddr(addressObj);

idObj.setFname("Test");

idObj.setLname("Tester");

ObjectMapper mapper = new ObjectMapper();

//Object to JSON in String

try {

String jsonInString = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(idObj);

System.out.println(jsonInString);

} catch (JsonProcessingException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

输出:

{

"fname" : "Test",

"lname" : "Tester",

"addr" : {

"street" : "Some Street",

"city" : "Chicago",

"zip" : 12345

}

}

以上是 将嵌套的Java对象转换为Jackson JSON 的全部内容, 来源链接: utcz.com/qa/431541.html

回到顶部