我们如何在Winform中的Datagridview中进行分页
我想在窗口窗体的datagridview中每页显示10条记录,用户必须单击“下一步”按钮以显示下10条记录。DataGridview中是否有一些属性,还是我需要创建一个自定义控件?
我需要做些什么才能做到这一点。
回答:
这是一个简单的工作示例,其中 BindingNavigator GUI控件通过将 BindingSource对象的DataSource设置为IListSource的自定义子类来使用它来识别分页符。(感谢关键人物的回答。)当用户单击“下一页”按钮时,将触发BindingNavigator,bindingSource1_CurrentChanged
并且您的代码可以获取所需的记录。说明:
- 创建Windows窗体应用程序
- 将BindingNavigator,DataGridView和BindingSource拖到窗体上
用以下代码替换Form1.cs:
using System;
using System.Collections.Generic;
using System.Windows.Forms;
namespace PagedDataGridView
{
public partial class Form1 : Form
{
private const int totalRecords = 43;
private const int pageSize = 10;
public Form1()
{
InitializeComponent();
dataGridView1.Columns.Add(new DataGridViewTextBoxColumn { DataPropertyName = "Index" });
bindingNavigator1.BindingSource = bindingSource1;
bindingSource1.CurrentChanged += new System.EventHandler(bindingSource1_CurrentChanged);
bindingSource1.DataSource = new PageOffsetList();
}
private void bindingSource1_CurrentChanged(object sender, EventArgs e)
{
// The desired page has changed, so fetch the page of records using the "Current" offset
int offset = (int)bindingSource1.Current;
var records = new List<Record>();
for (int i = offset; i < offset + pageSize && i < totalRecords; i++)
records.Add(new Record { Index = i });
dataGridView1.DataSource = records;
}
class Record
{
public int Index { get; set; }
}
class PageOffsetList : System.ComponentModel.IListSource
{
public bool ContainsListCollection { get; protected set; }
public System.Collections.IList GetList()
{
// Return a list of page offsets based on "totalRecords" and "pageSize"
var pageOffsets = new List<int>();
for (int offset = 0; offset < totalRecords; offset += pageSize)
pageOffsets.Add(offset);
return pageOffsets;
}
}
}
}
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