如何解决Spring-boot中的URI编码问题？

  • Z时代
  • 2024-01-10
  • 分类：问答

我正在使用spring-boot来托管http请求服务。

@RequestMapping("/extract")
    @SuppressWarnings("unchecked")
    @ResponseBody
    public ExtractionResponse extract(@RequestParam(value = "extractionInput") String input) {
        // LOGGER.info("input: " + input);
        JSONObject inputObject = JSON.parseObject(input);
        InputInfo inputInfo = new InputInfo();
        //Object object = inputObject.get(InputInfo.INPUT_INFO);
        JSONObject object = (JSONObject) inputObject.get(InputInfo.INPUT_INFO);
        String inputText = object.getString(InputInfo.INPUT_TEXT);
        inputInfo.setInputText(inputText);
        return jnService.getExtraction(inputInfo);
    }

出现％符号时，如下所示，它出现了错误：

 http://localhost:8090/extract?extractionInput={"inputInfo":{"inputText":"5.00%"}}

错误消息如下：

2018-10-09 at 19:12:53.340 [http-nio-8090-exec-1] INFO  org.apache.juli.logging.DirectJDKLog [180] [log] - Character decoding failed. Parameter [extractionInput] with value [{"inputInfo":{"inputText":"5.0022:%225.00%%22}}] has been ignored. Note that the name and value quoted here may be corrupted due to the failed decoding. Use debug level logging to see the original, non-corrupted values.
 Note: further occurrences of Parameter errors will be logged at DEBUG level.
2018-10-09 at 19:12:53.343 [http-nio-8090-exec-1] WARN  org.springframework.web.servlet.handler.AbstractHandlerExceptionResolver [140] [resolveException] - Resolved [org.springframework.web.bind.MissingServletRequestParameterException: Required String parameter 'extractionInput' is not present]

如何配置URI编码以在我的spring-boot配置中解决此问题？

编辑：可能的Java客户端代码发出请求：

public String process(String question) {
        QueryInfo queryInfo = getQueryInfo(question);
        ObjectMapper mapper = new ObjectMapper();
        mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
        String jsonResult = null;
        try {
            String jsonStr = mapper.writeValueAsString(queryInfo);
            String urlStr = Parameters.getQeWebserviceUrl() + URLEncoder.encode(jsonStr, "UTF-8");
            URL url = new URL(urlStr);
            BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream()));
            jsonResult = in.readLine();
            in.close();
        } catch (Exception jpe) {
            jpe.printStackTrace();
        } 
     return jsonResult
}

回答：

如果没有从客户端进行编码-如果在Servlet中处理请求之前遵循以下任何策略通过编码，您仍然可以实现此目标：

  • 使用Spring预处理器bean预处理控制器端点请求

  • 使用Spring AspectJ预处理控制器端点请求

  • 使用Spring Servlet过滤器预处理控制器端点请求

使用以上任何一种横切策略，您都可以对请求URL进行编码，然后传递回端点。

例如，以下是使用过滤器的一种实现。如果需要更好的性能，可以在此进行一些缓存。

@Component
public class SomeFilter implements Filter {
    private static final Logger LOGGER = LoggerFactory.getLogger(SomeFilter.class);
    @Override
    public void init(final FilterConfig filterConfig) throws ServletException {
    }
    @Override
    public void doFilter(final ServletRequest servletRequest, final ServletResponse servletResponse, final FilterChain filterChain) throws IOException, ServletException {
        HttpServletRequest request = (HttpServletRequest) servletRequest;
        HttpServletRequest modifiedRequest = new SomeHttpServletRequest(request);
        filterChain.doFilter(modifiedRequest, servletResponse);
    }
    @Override
    public void destroy() {
    }
    class SomeHttpServletRequest extends HttpServletRequestWrapper {
        HttpServletRequest request;
        SomeHttpServletRequest(final HttpServletRequest request) {
            super(request);
            this.request = request;
        }
        @Override
        public String getQueryString() {
            String queryString = request.getQueryString();
            LOGGER.info("Original query string: " + queryString);
            try {
                // You need to escape all your non encoded special characters here
                String specialChar = URLEncoder.encode("%", "UTF-8");
                queryString = queryString.replaceAll("\\%\\%", specialChar + "%");
                String decoded = URLDecoder.decode(queryString, "UTF-8");
                LOGGER.info("Modified query string: "  + decoded);
            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            }
            return queryString;
        }
        @Override
        public String getParameter(final String name) {
            String[] params = getParameterMap().get(name);
            return params.length > 0 ? params[0] : null;
        }
        @Override
        public Map<String, String[]> getParameterMap() {
            String queryString = getQueryString();
            return getParamsFromQueryString(queryString);
        }
        @Override
        public Enumeration<String> getParameterNames() {
            return Collections.enumeration(getParameterMap().keySet());
        }
        @Override
        public String[] getParameterValues(final String name) {
            return getParameterMap().get(name);
        }
        private Map<String, String[]> getParamsFromQueryString(final String queryString) {
            String decoded = "";
            try {
                decoded = URLDecoder.decode(queryString, "UTF-8");
            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            }
            String[] params = decoded.split("&");
            Map<String, List<String>> collect = Stream.of(params)
                .map(x -> x.split("="))
                .collect(Collectors.groupingBy(
                    x -> x[0],
                    Collectors.mapping(
                        x -> x.length > 1 ? x[1] : null,
                        Collectors.toList())));
            Map<String, String[]> result = collect.entrySet().stream()
                .collect(Collectors.toMap(
                    x -> x.getKey(),
                    x -> x.getValue()
                        .stream()
                        .toArray(String[]::new)));
            return result;
        }
    }
}

以上是 如何解决Spring-boot中的URI编码问题？ 的全部内容， 来源链接： utcz.com/qa/428581.html

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