JavaExecutorService在超时后中断任务

  • Z时代
  • 2024-01-10
  • 分类：问答

我正在寻找可以提供超时的ExecutorService实现。如果提交到ExecutorService的任务花费的时间超过了超时时间，则这些任务将被中断。实现这样的野兽并不是一个困难的任务，但是我想知道是否有人知道现有的实现。

这是我根据以下一些讨论得出的。任何意见？

import java.util.List;
import java.util.concurrent.*;
public class TimeoutThreadPoolExecutor extends ThreadPoolExecutor {
    private final long timeout;
    private final TimeUnit timeoutUnit;
    private final ScheduledExecutorService timeoutExecutor = Executors.newSingleThreadScheduledExecutor();
    private final ConcurrentMap<Runnable, ScheduledFuture> runningTasks = new ConcurrentHashMap<Runnable, ScheduledFuture>();
    public TimeoutThreadPoolExecutor(int corePoolSize, int maximumPoolSize, long keepAliveTime, TimeUnit unit, BlockingQueue<Runnable> workQueue, long timeout, TimeUnit timeoutUnit) {
        super(corePoolSize, maximumPoolSize, keepAliveTime, unit, workQueue);
        this.timeout = timeout;
        this.timeoutUnit = timeoutUnit;
    }
    public TimeoutThreadPoolExecutor(int corePoolSize, int maximumPoolSize, long keepAliveTime, TimeUnit unit, BlockingQueue<Runnable> workQueue, ThreadFactory threadFactory, long timeout, TimeUnit timeoutUnit) {
        super(corePoolSize, maximumPoolSize, keepAliveTime, unit, workQueue, threadFactory);
        this.timeout = timeout;
        this.timeoutUnit = timeoutUnit;
    }
    public TimeoutThreadPoolExecutor(int corePoolSize, int maximumPoolSize, long keepAliveTime, TimeUnit unit, BlockingQueue<Runnable> workQueue, RejectedExecutionHandler handler, long timeout, TimeUnit timeoutUnit) {
        super(corePoolSize, maximumPoolSize, keepAliveTime, unit, workQueue, handler);
        this.timeout = timeout;
        this.timeoutUnit = timeoutUnit;
    }
    public TimeoutThreadPoolExecutor(int corePoolSize, int maximumPoolSize, long keepAliveTime, TimeUnit unit, BlockingQueue<Runnable> workQueue, ThreadFactory threadFactory, RejectedExecutionHandler handler, long timeout, TimeUnit timeoutUnit) {
        super(corePoolSize, maximumPoolSize, keepAliveTime, unit, workQueue, threadFactory, handler);
        this.timeout = timeout;
        this.timeoutUnit = timeoutUnit;
    }
    @Override
    public void shutdown() {
        timeoutExecutor.shutdown();
        super.shutdown();
    }
    @Override
    public List<Runnable> shutdownNow() {
        timeoutExecutor.shutdownNow();
        return super.shutdownNow();
    }
    @Override
    protected void beforeExecute(Thread t, Runnable r) {
        if(timeout > 0) {
            final ScheduledFuture<?> scheduled = timeoutExecutor.schedule(new TimeoutTask(t), timeout, timeoutUnit);
            runningTasks.put(r, scheduled);
        }
    }
    @Override
    protected void afterExecute(Runnable r, Throwable t) {
        ScheduledFuture timeoutTask = runningTasks.remove(r);
        if(timeoutTask != null) {
            timeoutTask.cancel(false);
        }
    }
    class TimeoutTask implements Runnable {
        private final Thread thread;
        public TimeoutTask(Thread thread) {
            this.thread = thread;
        }
        @Override
        public void run() {
            thread.interrupt();
        }
    }
}

回答：

你可以为此使用ScheduledExecutorService。首先，你只提交一次即可立即开始，并保留创建的未来。之后，你可以提交新任务，该任务将在一段时间后取消保留的将来。

 ScheduledExecutorService executor = Executors.newScheduledThreadPool(2); 
 final Future handler = executor.submit(new Callable(){ ... });
 executor.schedule(new Runnable(){
     public void run(){
         handler.cancel();
     }      
 }, 10000, TimeUnit.MILLISECONDS);

这将使你的处理程序（主要功能被中断）执行10秒钟，然后将取消（即中断）该特定任务。

以上是 JavaExecutorService在超时后中断任务 的全部内容， 来源链接： utcz.com/qa/428222.html

回到顶部