Python Selenium获取所有“ href”属性

  • Z时代
  • 2024-01-10
  • 分类：问答

如何在此页面上获取此“ h2”标题的所有“ href”属性？

<h2 class="entry-title">
<a href="http://www.allitebooks.com/deep-learning-with-python-2/" rel="bookmark">Deep Learning with Python</a>
</h2>

我尝试过的没有得到href的是：

title = driver.find_elements_by_class_name('entry-title')
title[0].get_attribute('href')

这没有获得“ a”标签的链接。如果我在“ a”标签上找到了所有元素，它将返回页面上的每个href（这不是我想要的）。我只想返回上述标题，但能够获取其url“

href”属性。

回答：

这是从所有页面获取所有书籍的代码：

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome()
baseUrl = "http://www.allitebooks.com/page/1/?s=python"
driver.get(baseUrl)
# wait = WebDriverWait(driver, 5)
# wait.until(EC.visibility_of_element_located((By.CSS_SELECTOR, ".search-result-list li")))
# Get last page number
lastPage = int(driver.find_element(By.CSS_SELECTOR, ".pagination a:last-child").text)
# Get all HREFs for the first page and save them in hrefs list
js = 'return [...document.querySelectorAll(".entry-title a")].map(e=>e.href)'
hrefs = driver.execute_script(js)
# Iterate throw all pages and get all HREFs of books
for i in range(2, lastPage):
    driver.get("http://www.allitebooks.com/page/" + str(i) + "/?s=python")
    hrefs.extend(driver.execute_script(js))
for href in hrefs:
    print(href)

以上是 Python Selenium获取所有“ href”属性 的全部内容， 来源链接： utcz.com/qa/427707.html

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