$ {}在PHP语法中是什么意思?

我使用PHP已有很长时间了,但是我看到的类似,

${  }

确切地说,我在PHP Mongo页面中看到了这一点:

$m = new Mongo("mongodb://${username}:${password}@host");

那么,该怎么${ }办?这是相当难与谷歌或像字符PHP文件中进行搜索${}

回答:

${ }(美元大括号)被称为

之所以称其为“复杂”,是因为语法复杂,而是因为它允许使用复杂的表达式。

可以通过此语法包括具有字符串表示形式的任何标量变量,数组元素或对象属性。只需以与出现在字符串外部相同的方式编写表达式,然后将其包装在{和中即可}。由于{无法转义,因此仅在$紧随其后的才会识别此语法{。使用{\$得到文字{$。一些示例可以使您清楚:

<?php

// Show all errors

error_reporting(E_ALL);

$great = 'fantastic';

// Won't work, outputs: This is { fantastic}

echo "This is { $great}";

// Works, outputs: This is fantastic

echo "This is {$great}";

echo "This is ${great}";

// Works

echo "This square is {$square->width}00 centimeters broad.";

// Works, quoted keys only work using the curly brace syntax

echo "This works: {$arr['key']}";

// Works

echo "This works: {$arr[4][3]}";

// This is wrong for the same reason as $foo[bar] is wrong outside a

// string. In other words, it will still work, but only because PHP

// first looks for a constant named foo; an error of level E_NOTICE

// (undefined constant) will be thrown.

echo "This is wrong: {$arr[foo][3]}";

// Works. When using multi-dimensional arrays, always use braces around

// arrays when inside of strings

echo "This works: {$arr['foo'][3]}";

// Works.

echo "This works: " . $arr['foo'][3];

echo "This works too: {$obj->values[3]->name}";

echo "This is the value of the var named $name: {${$name}}";

echo "This is the value of the var named by the return value of "

. " getName(): {${getName()}}";

echo "This is the value of the var named by the return value of "

. "\$object->getName(): {${$object->getName()}}";

// Won't work, outputs: This is the return value of getName():

{getName()}

echo “This is the return value of getName(): {getName()}”;

?>

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