如何在Java中将字节大小转换成可读格式?
如何在Java中将字节大小转换为人类可读的格式?像1024应该变成“ 1 Kb”,而1024 * 1024应该变成“ 1 Mb”。
我有点讨厌为每个项目编写此实用程序方法。Apache Commons中是否为此有任何静态方法?
回答:
SI(1 k = 1,000)
public static String humanReadableByteCountSI(long bytes) { String s = bytes < 0 ? "-" : "";
long b = bytes == Long.MIN_VALUE ? Long.MAX_VALUE : Math.abs(bytes);
return b < 1000L ? bytes + " B"
: b < 999_950L ? String.format("%s%.1f kB", s, b / 1e3)
: (b /= 1000) < 999_950L ? String.format("%s%.1f MB", s, b / 1e3)
: (b /= 1000) < 999_950L ? String.format("%s%.1f GB", s, b / 1e3)
: (b /= 1000) < 999_950L ? String.format("%s%.1f TB", s, b / 1e3)
: (b /= 1000) < 999_950L ? String.format("%s%.1f PB", s, b / 1e3)
: String.format("%s%.1f EB", s, b / 1e6);
}
二进制(1 K = 1,024)
public static String humanReadableByteCountBin(long bytes) { long b = bytes == Long.MIN_VALUE ? Long.MAX_VALUE : Math.abs(bytes);
return b < 1024L ? bytes + " B"
: b <= 0xfffccccccccccccL >> 40 ? String.format("%.1f KiB", bytes / 0x1p10)
: b <= 0xfffccccccccccccL >> 30 ? String.format("%.1f MiB", bytes / 0x1p20)
: b <= 0xfffccccccccccccL >> 20 ? String.format("%.1f GiB", bytes / 0x1p30)
: b <= 0xfffccccccccccccL >> 10 ? String.format("%.1f TiB", bytes / 0x1p40)
: b <= 0xfffccccccccccccL ? String.format("%.1f PiB", (bytes >> 10) / 0x1p40)
: String.format("%.1f EiB", (bytes >> 20) / 0x1p40);
}
输出示例:
SI BINARY 0: 0 B 0 B
27: 27 B 27 B
999: 999 B 999 B
1000: 1.0 kB 1000 B
1023: 1.0 kB 1023 B
1024: 1.0 kB 1.0 KiB
1728: 1.7 kB 1.7 KiB
110592: 110.6 kB 108.0 KiB
7077888: 7.1 MB 6.8 MiB
452984832: 453.0 MB 432.0 MiB
28991029248: 29.0 GB 27.0 GiB
1855425871872: 1.9 TB 1.7 TiB
9223372036854775807: 9.2 EB 8.0 EiB (Long.MAX_VALUE)
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