MySQL GROUP BY两列

  • Z时代
  • 2024-01-10
  • 分类：问答

我试图在这里按多列分组-每张桌子上一列。

在这种情况下，我想通过将每个客户的当前投资组合和现金加在一起来找到每个客户的最高投资组合价值，但是一个客户可能拥有多个投资组合，因此我需要每个客户的最高投资组合。

目前，在下面的代码中，我会为每个客户的顶级投资组合多次获得相同的客户（而不是按客户ID分组）。

SELECT clients.id, clients.name, portfolios.id, SUM ( portfolios.portfolio +  portfolios.cash ) AS total
FROM clients, portfolios
WHERE clients.id = portfolios.client_id
GROUP BY portfolios.id, clients.id
ORDER BY total DESC
LIMIT 30

回答：

首先，让我们做一些测试数据：

create table client (client_id integer not null primary key auto_increment,
                     name varchar(64));
create table portfolio (portfolio_id integer not null primary key auto_increment,
                        client_id integer references client.id,
                        cash decimal(10,2),
                        stocks decimal(10,2));
insert into client (name) values ('John Doe'), ('Jane Doe');
insert into portfolio (client_id, cash, stocks) values (1, 11.11, 22.22),
                                                       (1, 10.11, 23.22),
                                                       (2, 30.30, 40.40),
                                                       (2, 40.40, 50.50);

如果您不需要投资组合ID，这很容易：

select client_id, name, max(cash + stocks)
from client join portfolio using (client_id)
group by client_id
+-----------+----------+--------------------+
| client_id | name     | max(cash + stocks) |
+-----------+----------+--------------------+
|         1 | John Doe |              33.33 | 
|         2 | Jane Doe |              90.90 | 
+-----------+----------+--------------------+

由于您需要投资组合ID，因此事情变得更加复杂。让我们逐步进行。首先，我们将编写一个子查询，该子查询返回每个客户的最大投资组合值：

select client_id, max(cash + stocks) as maxtotal
from portfolio
group by client_id
+-----------+----------+
| client_id | maxtotal |
+-----------+----------+
|         1 |    33.33 | 
|         2 |    90.90 | 
+-----------+----------+

然后，我们将查询投资组合表，但要使用上一个子查询的联接，以仅保留那些总价值对客户而言最大的投资组合：

 select portfolio_id, cash + stocks from portfolio 
 join (select client_id, max(cash + stocks) as maxtotal 
       from portfolio
       group by client_id) as maxima
 using (client_id)
 where cash + stocks = maxtotal
+--------------+---------------+
| portfolio_id | cash + stocks |
+--------------+---------------+
|            5 |         33.33 | 
|            6 |         33.33 | 
|            8 |         90.90 | 
+--------------+---------------+

最后，我们可以连接到客户表（就像您所做的那样），以便包括每个客户的名称：

select client_id, name, portfolio_id, cash + stocks
from client
join portfolio using (client_id)
join (select client_id, max(cash + stocks) as maxtotal
      from portfolio 
      group by client_id) as maxima
using (client_id)
where cash + stocks = maxtotal
+-----------+----------+--------------+---------------+
| client_id | name     | portfolio_id | cash + stocks |
+-----------+----------+--------------+---------------+
|         1 | John Doe |            5 |         33.33 | 
|         1 | John Doe |            6 |         33.33 | 
|         2 | Jane Doe |            8 |         90.90 | 
+-----------+----------+--------------+---------------+

请注意，这将返回John Doe的两行，因为他有两个总价值完全相同的投资组合。为了避免这种情况并选择任意的顶级投资组合，请在GROUP BY子句上进行标记：

select client_id, name, portfolio_id, cash + stocks
from client
join portfolio using (client_id)
join (select client_id, max(cash + stocks) as maxtotal
      from portfolio 
      group by client_id) as maxima
using (client_id)
where cash + stocks = maxtotal
group by client_id, cash + stocks
+-----------+----------+--------------+---------------+
| client_id | name     | portfolio_id | cash + stocks |
+-----------+----------+--------------+---------------+
|         1 | John Doe |            5 |         33.33 | 
|         2 | Jane Doe |            8 |         90.90 | 
+-----------+----------+--------------+---------------+

以上是 MySQL GROUP BY两列 的全部内容， 来源链接： utcz.com/qa/424684.html

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