Spring @RestController自定义JSON反序列化器

  • Z时代
  • 2024-01-10
  • 分类：问答

我想对某些类使用自定义JSON反序列化器（在此处 ），但无法正常工作。自定义解串器只是不被调用。

我使用Spring Boot 1.2。

解串器：

public class ModelDeserializer extends JsonDeserializer<Role> {
    @Override
    public Role deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException, JsonProcessingException {
        return null; // this is what should be called but it isn't
    }
}

控制器：

@RestController
public class RoleController {
    @RequestMapping(value = "/role", method = RequestMethod.POST)
    public Object createRole(Role role) {
        // ... this is called
    }
}

  1. @JsonDeserialize 在角色上

    @JsonDeserialize(using = ModelDeserializer.class)

    public class Role extends Model {

    }

  2. Jackson2ObjectMapperBuilder Java Config中的bean

    @Bean

    public Jackson2ObjectMapperBuilder jacksonBuilder() {

    Jackson2ObjectMapperBuilder builder = new Jackson2ObjectMapperBuilder();

    builder.deserializerByType(Role.class, new ModelDeserializer());

    return builder;

    }

我究竟做错了什么？

可能是@RestController由于它与@Controller…

回答：

首先，您不需要重写Jackson2ObjectMapperBuilder即可添加自定义反序列化器。当您无法添加@JsonDeserialize注释时，应使用此方法。您应该使用@JsonDeserialize或覆盖Jackson2ObjectMapperBuilder。

缺少的是@RequestBody注释：

@RestController
public class JacksonCustomDesRestEndpoint {
    @RequestMapping(value = "/role", method = RequestMethod.POST, consumes = MediaType.APPLICATION_JSON_VALUE, produces = MediaType.APPLICATION_JSON_VALUE)
    @ResponseBody
    public Object createRole(@RequestBody Role role) {
        return role;
    }
}
@JsonDeserialize(using = RoleDeserializer.class)
public class Role {
    // ......
}
public class RoleDeserializer extends JsonDeserializer<Role> {
    @Override
    public Role deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException, JsonProcessingException {
        // .................
        return something;
    }
}

以上是 Spring @RestController自定义JSON反序列化器 的全部内容， 来源链接： utcz.com/qa/424580.html

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