在Swift中生成随机字母数字字符串

  • Z时代
  • 2024-01-10
  • 分类：问答

如何在Swift中生成随机的字母数字字符串？

回答：

Swift

4.2在处理随机值和元素方面引入了重大改进。您可以在此处阅读有关这些改进的更多信息。这是减少到几行的方法：

func randomString(length: Int) -> String {
  let letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
  return String((0..<length).map{ _ in letters.randomElement()! })
}

func randomString(length: Int) -> String {
    let letters : NSString = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
    let len = UInt32(letters.length)
    var randomString = ""
    for _ in 0 ..< length {
        let rand = arc4random_uniform(len)
        var nextChar = letters.character(at: Int(rand))
        randomString += NSString(characters: &nextChar, length: 1) as String
    }
    return randomString
}

func randomStringWithLength (len : Int) -> NSString {
    let letters : NSString = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
    var randomString : NSMutableString = NSMutableString(capacity: len)
    for (var i=0; i < len; i++){
        var length = UInt32 (letters.length)
        var rand = arc4random_uniform(length)
        randomString.appendFormat("%C", letters.characterAtIndex(Int(rand)))
    }
    return randomString
}

以上是 在Swift中生成随机字母数字字符串 的全部内容， 来源链接： utcz.com/qa/424466.html

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