如何在Java中获取屏幕DPI？

Z时代
2024-01-10
分类：问答

我正在开发一个需要屏幕DPI的应用程序。我检查了几个论坛，并获得了一个代码段，内容如下：

Dimension screen = java.awt.Toolkit.getDefaultToolkit().getScreenSize();
System.out.println("screen width: "+screen.getWidth()); 
System.out.println("screen height: "+screen.getHeight()); 
int pixelPerInch=java.awt.Toolkit.getDefaultToolkit().getScreenResolution(); 
System.out.println("pixelPerInch: "+pixelPerInch);
double height=screen.getHeight()/pixelPerInch; 
double width=screen.getWidth()/pixelPerInch; 
double x=Math.pow(height,2); 
double y=Math.pow(width,2);

但是无论我的屏幕分辨率pixelPerInch值是多少，该值都保持不变，为96。代码有什么问题？

swt对于同一件事，我得到了另一个代码，如下所示：

  import org.eclipse.swt.graphics.Device;
  import org.eclipse.swt.widgets.Display;
  import org.eclipse.swt.widgets.Shell;
  public class MainClass {
  public void run() {
  Display display = new Display();
  Shell shell = new Shell(display);
  shell.setText("Display Device");
  createContents(shell);
  shell.pack();
  shell.open();
  while (!shell.isDisposed()) {
    if (!display.readAndDispatch()) {
      display.sleep();
    }
  }
  display.dispose();
}
private void createContents(Shell shell) {
  Device device = shell.getDisplay();
  System.out.println("getBounds(): "+ device.getBounds());
  System.out.println("getClientArea(): "+device.getClientArea());
  System.out.println("getDepth(): "+device.getDepth());
  System.out.println("getDPI(): "+device.getDPI());
  device.setWarnings(true);
  System.out.println("Warnings supported: "+device.getWarnings());
}
public static void main(String[] args) {
  new MainClass().run();
}