从PHP中的绝对路径获取相对路径
键入标题时,我注意到有关此问题的一些类似问题,但它们似乎不在PHP中。那么用PHP函数解决该问题的方法是什么?
待指定。
$a="/home/apache/a/a.php";$b="/home/root/b/b.php";
$relpath = getRelativePath($a,$b); //needed function,should return '../../root/b/b.php'
有什么好主意吗?谢谢。
回答:
试试这个:
function getRelativePath($from, $to){
// some compatibility fixes for Windows paths
$from = is_dir($from) ? rtrim($from, '\/') . '/' : $from;
$to = is_dir($to) ? rtrim($to, '\/') . '/' : $to;
$from = str_replace('\\', '/', $from);
$to = str_replace('\\', '/', $to);
$from = explode('/', $from);
$to = explode('/', $to);
$relPath = $to;
foreach($from as $depth => $dir) {
// find first non-matching dir
if($dir === $to[$depth]) {
// ignore this directory
array_shift($relPath);
} else {
// get number of remaining dirs to $from
$remaining = count($from) - $depth;
if($remaining > 1) {
// add traversals up to first matching dir
$padLength = (count($relPath) + $remaining - 1) * -1;
$relPath = array_pad($relPath, $padLength, '..');
break;
} else {
$relPath[0] = './' . $relPath[0];
}
}
}
return implode('/', $relPath);
}
这将给
$a="/home/a.php";$b="/home/root/b/b.php";
echo getRelativePath($a,$b), PHP_EOL; // ./root/b/b.php
和
$a="/home/apache/a/a.php";$b="/home/root/b/b.php";
echo getRelativePath($a,$b), PHP_EOL; // ../../root/b/b.php
和
$a="/home/root/a/a.php";$b="/home/apache/htdocs/b/en/b.php";
echo getRelativePath($a,$b), PHP_EOL; // ../../apache/htdocs/b/en/b.php
和
$a="/home/apache/htdocs/b/en/b.php";$b="/home/root/a/a.php";
echo getRelativePath($a,$b), PHP_EOL; // ../../../../root/a/a.php
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