Java中的curl命令
首先,我已经看过几个文档,关于同一文档的stackoverflow问题。我在尝试运行命令时遇到了项目特定的问题:
curl -u username:password https://example.com/xyz/abc
从mac终端,我得到了所需的json格式数据。但是从Java代码运行相同的命令,控制台中出现Unauthorized 401错误。我的代码是:
String username="myusername"; String password="mypassword";
String url="https://www.example.com/xyz/abc";
String[] command = {"curl", "-u" ,"Accept:application/json", username, ":" , password , url};
ProcessBuilder process = new ProcessBuilder(command);
Process p;
try
{
p = process.start();
BufferedReader reader = new BufferedReader(new InputStreamReader(p.getInputStream()));
StringBuilder builder = new StringBuilder();
String line = null;
while ( (line = reader.readLine()) != null) {
builder.append(line);
builder.append(System.getProperty("line.separator"));
}
String result = builder.toString();
System.out.print(result);
}
catch (IOException e)
{ System.out.print("error");
e.printStackTrace();
}
我收到未经授权的401错误和一堆html标签。这似乎是一个重复性的问题,但我已经尝试了所有方法。我知道替代方法是使用http响应方法,但特别是我想使用curl命令。提前致谢。
回答:
尝试更改此行
String[] command = {"curl", "-u" ,"Accept:application/json", username, ":" , password , url};
进入
String[] command = {"curl", "-H", "Accept:application/json", "-u", username+":"+password , url};
以上是 Java中的curl命令 的全部内容, 来源链接: utcz.com/qa/417081.html