从Java执行Shell脚本，具有读取操作的Shell脚本

Z时代
2024-01-10
分类：问答

我有一个读取输入的Shell脚本

#!/bin/bash
echo "Type the year that you want to check (4 digits), followed by [ENTER]:"
read year
echo $year

我正在使用JAVA APi执行此Shell脚本

ProcessBuilder pb = new ProcessBuilder("/bin/bash", "/junk/leaptest.sh");
final Process process = pb.start();
InputStream is = process.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
String line;
while ((line = br.readLine()) != null) {
    System.out.println(line);       
}
System.out.println("Program terminated!");

在Java控制台中，我可以看到输出

键入要检查的年份（4位数字），然后按[ENTER]：

现在，如何将值传递到我脚本中的Shell脚本中的实际问题是如何读取变量“ year”

我已经按照建议编辑了代码，但在我们更正的地方无法正常工作

ProcessBuilder pb = new ProcessBuilder("/bin/bash", "-c", "/junk/leaptest.sh");
final Process process = pb.start();
InputStream is = process.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
String line;
/*
 * OutputStream os = process.getOutputStream(); PrintWriter pw = new
 * PrintWriter(os);
 */
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(process.getOutputStream()));
while ((line = br.readLine()) != null) {
    System.out.println(line);
    // pw.println("8999");
    bw.write("2012");
}
System.out.println("Program terminated!");