如何ungzip(解压缩)NodeJS请求的模块gzip响应主体?
如何在请求的模块响应中解压缩压缩的正文?
我已经在网上尝试了几个示例,但似乎都没有用。
request(url, function(err, response, body) { if(err) {
handleError(err)
} else {
if(response.headers['content-encoding'] == 'gzip') {
// How can I unzip the gzipped string body variable?
// For instance, this url:
// http://highsnobiety.com/2012/08/25/norse-projects-fall-2012-lookbook/
// Throws error:
// { [Error: incorrect header check] errno: -3, code: 'Z_DATA_ERROR' }
// Yet, browser displays page fine and debugger shows its gzipped
// And unzipped by browser fine...
if(response.headers['content-encoding'] && response.headers['content-encoding'].toLowerCase().indexOf('gzip') > -1) {
var body = response.body;
zlib.gunzip(response.body, function(error, data) {
if(!error) {
response.body = data.toString();
} else {
console.log('Error unzipping:');
console.log(error);
response.body = body;
}
});
}
}
}
}
回答:
我也无法获得工作请求,因此最终使用了http。
var http = require("http"), zlib = require("zlib");
function getGzipped(url, callback) {
// buffer to store the streamed decompression
var buffer = [];
http.get(url, function(res) {
// pipe the response into the gunzip to decompress
var gunzip = zlib.createGunzip();
res.pipe(gunzip);
gunzip.on('data', function(data) {
// decompression chunk ready, add it to the buffer
buffer.push(data.toString())
}).on("end", function() {
// response and decompression complete, join the buffer and return
callback(null, buffer.join(""));
}).on("error", function(e) {
callback(e);
})
}).on('error', function(e) {
callback(e)
});
}
getGzipped(url, function(err, data) {
console.log(data);
});
以上是 如何ungzip(解压缩)NodeJS请求的模块gzip响应主体? 的全部内容, 来源链接: utcz.com/qa/415403.html