使用Python以MySQL格式打印结果

  • Z时代
  • 2024-01-10
  • 分类：问答

与MySQL使用Python在控制台中打印结果一样，最简单的打印MySQL查询结果的方法是什么？例如，我想得到类似的东西：

+---------------------+-----------+---------+
| font                | documents | domains |
+---------------------+-----------+---------+
| arial               |     99854 |    5741 |
| georgia             |     52388 |    1955 |
| verdana             |     43219 |    2388 |
| helvetica neue      |     22179 |    1019 |
| helvetica           |     16753 |    1036 |
| lucida grande       |     15431 |     641 |
| tahoma              |     10038 |     594 |
| trebuchet ms        |      8868 |     417 |
| palatino            |      5794 |     177 |
| lucida sans unicode |      3525 |     116 |
| sans-serif          |      2947 |     216 |
| times new roman     |      2554 |     161 |
| proxima-nova        |      2076 |      36 |
| droid sans          |      1773 |      78 |
| calibri             |      1735 |      64 |
| open sans           |      1479 |      60 |
| segoe ui            |      1273 |      57 |
+---------------------+-----------+---------+
17 rows in set (19.43 sec)

注意：我不知道每列的最大宽度是先验的，但是我希望能够不重复两次就可以做到这一点。是否应为每列添加查询的length（）？MySQL如何做到这一点，以免严重影响内存或处理时间？

编辑

我认为这与问题无关，但这是我发送的查询：

SELECT font.font as font,count(textfont.textid) as documents, count(DISTINCT td.domain) as domains
FROM textfont 
RIGHT JOIN font
ON textfont.fontid = font.fontid
RIGHT JOIN (
        SELECT text.text as text,url.domain as domain, text.textid as textid 
        FROM text 
        RIGHT JOIN url 
        ON text.texturl = url.urlid) as td 
ON textfont.textid = td.textid
WHERE textfont.fontpriority <= 0 
AND textfont.textlen > 100
GROUP BY font.font 
HAVING documents >= 1000 AND domains >= 10
ORDER BY 2 DESC;

这是我使用的python代码：

import MySQLdb as mdb
print "%s\t\t\t%s\t\t%s" % ("font","documents","domains")
res = cur.execute(query , (font_priority,text_len,min_texts,min_domains))
for res in cur.fetchall():
    print "%s\t\t\t%d\t\t%d" % (res[0],res[1],res[2])

但是此代码由于宽度不同而产生混乱的输出。

回答：

采用 prettytable

x = PrettyTable(["City name", "Area", "Population", "Annual Rainfall"])
x.set_field_align("City name", "l") # Left align city names
x.set_padding_width(1) # One space between column edges and contents (default)
x.add_row(["Adelaide",1295, 1158259, 600.5])
x.add_row(["Brisbane",5905, 1857594, 1146.4])
x.add_row(["Darwin", 112, 120900, 1714.7])
x.add_row(["Hobart", 1357, 205556, 619.5])
x.add_row(["Sydney", 2058, 4336374, 1214.8])
x.add_row(["Melbourne", 1566, 3806092, 646.9])
x.add_row(["Perth", 5386, 1554769, 869.4])
print x
+-----------+------+------------+-----------------+
| City name | Area | Population | Annual Rainfall |
+-----------+------+------------+-----------------+
| Adelaide  | 1295 |  1158259   |      600.5      |
| Brisbane  | 5905 |  1857594   |      1146.4     |
| Darwin    | 112  |   120900   |      1714.7     |
| Hobart    | 1357 |   205556   |      619.5      |
| Sydney    | 2058 |  4336374   |      1214.8     |
| Melbourne | 1566 |  3806092   |      646.9      |
| Perth     | 5386 |  1554769   |      869.4      |
+-----------+------+------------+-----------------+

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