如何在JavaScript或jQuery中过滤JSON数据?
如何使用Javascript或jQuery过滤JSON数据?
这是我的JSON数据:
[{"name":"Lenovo Thinkpad 41A4298","website":"google"},{"name":"Lenovo Thinkpad 41A2222","website":"google"},
{"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"},
{"name":"Lenovo Thinkpad 41A424448","website":"google"},
{"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"},
{"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}]
obj1 = JSON.parse(jsondata);
现在我只想要包含网站的名称和网站数据等于
回答:
这是您应该怎么做的方法:(适用于Google查找)
$([ {"name":"Lenovo Thinkpad 41A4298","website":"google222"},
{"name":"Lenovo Thinkpad 41A2222","website":"google"}
])
.filter(function (i,n){
return n.website==='google';
});
解决方案:(Salman’s)
$.grep( [{"name":"Lenovo Thinkpad 41A4298","website":"google"},{"name":"Lenovo Thinkpad 41A2222","website":"google"}], function( n, i ) { return n.website==='google';
});
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