在Swift中格式化电话号码

  • Z时代
  • 2024-01-10
  • 分类：问答

一旦用户开始将电话号码键入此格式类型，0 (555) 444 66

77并且我可以正常工作，我就在格式化文本文件中的文本，但是一旦我从服务器上获得了电话号码，我就这样得到了，05554446677所以请您告诉我如何编辑它我从服务器获得相同格式的文件吗？

输入开始后的代码：

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    if textField == phoneNumberTextField{
        var newString = (textField.text as NSString).stringByReplacingCharactersInRange(range, withString: string)
        var components = newString.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet)
        var decimalString = "".join(components) as NSString
        var length = decimalString.length
        var hasLeadingOne = length > 0 && decimalString.characterAtIndex(0) == (1 as unichar)
        if length == 0 || (length > 11 && !hasLeadingOne) || length > 12{
            var newLength = (textField.text as NSString).length + (string as NSString).length - range.length as Int
            return (newLength > 11) ? false : true
        }
        var index = 0 as Int
        var formattedString = NSMutableString()
        if hasLeadingOne{
            formattedString.appendString("1 ")
            index += 1
        }
        if (length - index) > 1{
            var zeroNumber = decimalString.substringWithRange(NSMakeRange(index, 1))
            formattedString.appendFormat("%@ ", zeroNumber)
            index += 1
        }
        if (length - index) > 3{
            var areaCode = decimalString.substringWithRange(NSMakeRange(index, 3))
            formattedString.appendFormat("(%@) ", areaCode)
            index += 3
        }
        if (length - index) > 3{
            var prefix = decimalString.substringWithRange(NSMakeRange(index, 3))
            formattedString.appendFormat("%@ ", prefix)
            index += 3
        }
        if (length - index) > 3{
            var prefix = decimalString.substringWithRange(NSMakeRange(index, 2))
            formattedString.appendFormat("%@ ", prefix)
            index += 2
        }
        var remainder = decimalString.substringFromIndex(index)
        formattedString.appendString(remainder)
        textField.text = formattedString as String
        return false
    }else{
        return true
    }
}

回答：

用String中的字符进行操作不是很简单。您需要遵循以下条件：

let s = "05554446677"
let s2 = String(format: "%@ (%@) %@ %@ %@", s.substringToIndex(s.startIndex.advancedBy(1)),
    s.substringWithRange(s.startIndex.advancedBy(1) ... s.startIndex.advancedBy(3)),
    s.substringWithRange(s.startIndex.advancedBy(4) ... s.startIndex.advancedBy(6)),
    s.substringWithRange(s.startIndex.advancedBy(7) ... s.startIndex.advancedBy(8)),
    s.substringWithRange(s.startIndex.advancedBy(9) ... s.startIndex.advancedBy(10))
)

let s = "05554446677"
let s2 = String(format: "%@ (%@) %@ %@ %@", s.substringToIndex(advance(s.startIndex, 1)),
    s.substringWithRange(advance(s.startIndex, 1) ... advance(s.startIndex, 3)),
    s.substringWithRange(advance(s.startIndex, 4) ... advance(s.startIndex, 6)),
    s.substringWithRange(advance(s.startIndex, 7) ... advance(s.startIndex, 8)),
    s.substringWithRange(advance(s.startIndex, 9) ... advance(s.startIndex, 10))
)

代码将打印 0 (555) 444 66 77

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