在Eclipse中创建一个简单的JAX-WS WebService

Z时代
2024-01-10
分类：问答

我正在尝试在Eclipse中创建一个简单的Web服务。首先，我创建了一个空的Java项目，并将以下三个文件添加到src文件夹中

Greeting.java

    package com.alfaisaliah;
    import javax.jws.WebService;
    import javax.jws.WebMethod;
    @WebService
    public interface Greeting {
        @WebMethod
        String sayHello(String name);
    }

GreetingImp.java

    package com.alfaisaliah;
    import javax.jws.WebService;
    @WebService(endpointInterface="com.alfaisaliah.Greeting")
    public class GreetingImp implements Greeting {
        @Override
        public String sayHello(String name) {
            return "Hello " + name;
        }
    }

WSPublisher

    package com.alfaisaliah;
    import javax.xml.ws.Endpoint;
    public class WSPublisher {
        public static void main(String[] args){
            Endpoint.publish("http://localhost:8081/WS/Greeting", new GreetingImp());
        }
    }

我正在遵循的教程未指定任何服务器来运行Web服务！我想知道是否需要指定任何服务器。我已经有了Tomcat

v5.5，但在此示例中未使用它。每当我将这个项目作为Java项目运行时，都会出现某种错误。任何人都可以帮助我确定我的问题试图在哪里运行Web服务。这是eclipse控制台的输出

Feb 26, 2012 12:01:00 PM com.sun.xml.internal.ws.model.RuntimeModeler getRequestWrapperClass INFO: Dynamically creating request wrapper Class com.alfaisaliah.jaxws.SayHello Feb 26, 2012 12:01:00 PM com.sun.xml.internal.ws.model.RuntimeModeler getResponseWrapperClass INFO: Dynamically creating response wrapper bean Class com.alfaisaliah.jaxws.SayHelloResponse

另外，当我再次运行该项目时，它说该地址已被使用

Feb 26, 2012 12:01:00 PM com.sun.xml.internal.ws.model.RuntimeModeler getRequestWrapperClass INFO: Dynamically creating request wrapper Class com.alfaisaliah.jaxws.SayHello Feb 26, 2012 12:01:00 PM com.sun.xml.internal.ws.model.RuntimeModeler getResponseWrapperClass INFO: Dynamically creating response wrapper bean Class com.alfaisaliah.jaxws.SayHelloResponse Exception in thread "main" com.sun.xml.internal.ws.server.ServerRtException: Server Runtime Error: java.net.BindException: Address already in use

谢谢您的帮助：)