从Tiles视图（JSP）访问Spring bean

• Z时代
• 2024-01-10
• 分类：问答

在Spring MVC中，我可以使用JstlView的posedContextBeanNames（或ExposureContextBeansAsAttributes）在JSP中访问我的bean。例如，然后，在我的JSP中，我可以编写（$ {properties.myProperty）。但是，当相同的JSP是tile视图的一部分时，将无法访问这些属性。是否可以正确配置Tiles或以其他方式访问这些属性？

我正在使用Spring MVC 3.0.2和Tiles 2.2.1。这是我的一些配置：

<bean id="tilesViewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
    <property name="order" value="1"/>
    <property name="viewClass" value="org.springframework.web.servlet.view.tiles2.TilesView" />
</bean> 
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
    <property name="order" value="2"/>
    <property name="prefix" value="/WEB-INF/views/"/>
    <property name="suffix" value=".jsp"/>
    <property name="exposedContextBeanNames">
        <list><value>properties</value></list>
    </property>
</bean>

编辑：我已经实现了Skaffman的解决方案。

TilesExposedBeansViewResolver.java：
package es.kcsolutions.util.spring.servlet.view;
import org.springframework.web.servlet.view.*;
public class TilesExposingBeansViewResolver extends UrlBasedViewResolver {
    private Boolean exposeContextBeansAsAttributes;
    private String[] exposedContextBeanNames;
    public void setExposeContextBeansAsAttributes(boolean exposeContextBeansAsAttributes) {
        this.exposeContextBeansAsAttributes = exposeContextBeansAsAttributes;
    }
    public void setExposedContextBeanNames(String[] exposedContextBeanNames) {
        this.exposedContextBeanNames = exposedContextBeanNames;
    }
    @Override
    protected AbstractUrlBasedView buildView(String viewName) throws Exception {
        AbstractUrlBasedView superView = super.buildView(viewName);
        if (superView instanceof TilesExposingBeansView) {
            TilesExposingBeansView view = (TilesExposingBeansView) superView;
            if (this.exposeContextBeansAsAttributes != null) view.setExposeContextBeansAsAttributes(this.exposeContextBeansAsAttributes);
            if (this.exposedContextBeanNames != null) view.setExposedContextBeanNames(this.exposedContextBeanNames);
        }
        return superView;
    }
}

TilesExposedBeansView.java：

package es.kcsolutions.util.spring.servlet.view;
import java.util.*;
import javax.servlet.http.*;
import org.springframework.web.context.support.ContextExposingHttpServletRequest;
import org.springframework.web.servlet.view.tiles2.TilesView;
public class TilesExposingBeansView extends TilesView {
    private boolean exposeContextBeansAsAttributes = false;
    private Set<String> exposedContextBeanNames;
    public void setExposeContextBeansAsAttributes(boolean exposeContextBeansAsAttributes) {
        this.exposeContextBeansAsAttributes = exposeContextBeansAsAttributes;
    }
    public void setExposedContextBeanNames(String[] exposedContextBeanNames) {
        this.exposedContextBeanNames = new HashSet<String>(Arrays.asList(exposedContextBeanNames));
    } 
    protected HttpServletRequest getRequestToExpose(HttpServletRequest originalRequest) {
        if (this.exposeContextBeansAsAttributes || this.exposedContextBeanNames != null) 
        return new ContextExposingHttpServletRequest(originalRequest, getWebApplicationContext(), this.exposedContextBeanNames);
        return originalRequest;
    }
    @Override
    protected void renderMergedOutputModel(Map<String, Object> model, HttpServletRequest request, HttpServletResponse response) throws Exception {
        HttpServletRequest requestToExpose = getRequestToExpose(request);
        exposeModelAsRequestAttributes(model, requestToExpose);
        super.renderMergedOutputModel(model, requestToExpose, response);
    }
}

Spring配置：

    <bean id="tilesViewResolver" class="es.kcsolutions.util.spring.servlet.view.TilesExposingBeansViewResolver">
        <property name="order" value="1"/>
        <property name="viewClass" value="es.kcsolutions.util.spring.servlet.view.TilesExposingBeansView"/>
        <property name="exposedContextBeanNames">
            <list><value>properties</value></list>
        </property>
    </bean> 

如果有问题，请查看TilesExposedBeansView.renderMergedOutputModel。我做了一些测试，但是也许有必要做更多的事情。

回答：

你是否尝试在xml配置文件中使用ServletContextAttributeExporter？

<bean
    class="org.springframework.web.context.support.ServletContextAttributeExporter">
    <property name="attributes">
        <map>
            <entry key="<bean key here>">
                <ref bean="<bean name here" />
            </entry>
        </map>
    </property>
</bean>

以上是 从Tiles视图（JSP）访问Spring bean 的全部内容， 来源链接： utcz.com/qa/410319.html