Spring MVC @RequestBody接收具有非原始属性的对象包装
我按如下方式创建JSON:
var manager = { username: "admin",
password: "admin"
};
var userToSubscribe = {
username: "newuser",
password: "newpassword",
email: "user@1and1.es"
};
var openid = "myopenid";
var subscription = {
manager: manager,
userToSubscribe : userToSubscribe,
openid : openid
};
$.ajax({
url: '/myapp/rest/subscribeUser.json',
type: 'POST',
dataType: 'json',
contentType: 'application/json',
mimeType: 'application/json',
data: JSON.stringify({subscription : subscription})
});
这是发送的JSON:
{"subscription":{"manager":{"username":"admin","password":"admin"},"userToSubscribe":{"username":"newuser","password":"newpassword","email":"user@1and1.es"},"openid":"myopenid"}}
我想将此JSON映射到Wrapper类。这是包装器:
private class Subscription{ private User manager;
private User userToSubscribe;
private String openid;
public User getManager() {
return manager;
}
public void setManager(User manager) {
this.manager = manager;
}
public User getUserToSubscribe() {
return userToSubscribe;
}
public void setUserToSubscribe(User userToSubscribe) {
this.userToSubscribe = userToSubscribe;
}
public String getOpenid() {
return openid;
}
public void setOpenid(String openid) {
this.openid = openid;
}
}
pom.xml中的杰克逊依赖关系(我正在使用spring 3.1.0.RELEASE):
<dependency> <groupId>org.codehaus.jackson</groupId>
<artifactId>jackson-mapper-asl</artifactId>
<version>1.9.10</version>
</dependency>
rest-servlet.xml中的映射
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"> <property name="messageConverters">
<list>
<ref bean="jsonConverter" />
</list>
</property>
</bean>
<bean id="jsonConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter">
<property name="supportedMediaTypes" value="application/json" />
</bean>
和控制器方法的标头:
public @ResponseBody SimpleMessage subscribeUser(@RequestBody Subscription subscription)
由于POST,我收到400错误请求请求错误。是否可以执行此操作,或者我是否需要使用@RequestBody
String进行操作或@RequestBody
Map<String,Object>自己解码JSON?
谢谢!
回答:
我要回答我自己的问题。首先要特别感谢Sotirios Delimanolis,因为他给了我钥匙以调查发生了什么。
如您所知,我从视图创建以下json:
{"manager":{"username":"admin","password":"admin"},"userToSubscribe":{"username":"newuser","password":"newpassword","email":"user@1and1.es"},"openid":"https://myopenid..."}
我做了一点修改,因为我意识到创建对象订阅和var订阅不是必需的。如果您像这样构建JSON,它将可以完美地工作:
var manager = { username: "admin",
password: "admin"
};
var userToSubscribe = {
username: "newuser",
password: "newpassword",
email: "user@1and1.es"
};
var openid = "https://myopenid...";
$.ajax({
url: '/dp/rest/isUserSuscribed.json',
type: 'POST',
dataType: 'json',
contentType: 'application/json',
mimeType: 'application/json',
data: JSON.stringify({manager : manager, userToSubscribe : userToSubscribe, openid : openid})
});
控制器收到以下json:
@RequestMapping(method=RequestMethod.POST, value="/isUserSuscribed.json")public @ResponseBody ResponseMessageElement<Boolean> isUserSuscribed(@RequestBody SubscriptionWrapper subscription){
还有SubscriptionWrapper …
private static class SubscriptionWrapper { BasicUser manager;
BasicUser userToSubscribe;
String openid;
public BasicUser getManager() {
return manager;
}
public void setManager(BasicUser manager) {
this.manager = manager;
}
public BasicUser getUserToSubscribe() {
return userToSubscribe;
}
public void setUserToSubscribe(BasicUser userToSubscribe) {
this.userToSubscribe = userToSubscribe;
}
public String getOpenid() {
return openid;
}
public void setOpenid(String openid) {
this.openid = openid;
}
}
那是什么问题 我收到了一个不正确的Request
400错误…我按照Sotirios的建议调试了MappingJackson2HttpMessageConverter,但发生了异常(没有合适的构造函数)。无论此类不是静态的,Jackson
Mapping都无法构建内部类。将SubscriptionWrapper设置为静态是解决我的问题的方法。
您还可以检查以下答案: http://stackoverflow.com/questions/8526333/jackson-error-no-
suitable-constructor
http://stackoverflow.com/questions/12139380/how-to-convert-json-into-pojo-in-
java-using-jackson
如果您有反序列化的问题,请检查以下内容: http://stackoverflow.com/questions/17400850/is-jackson-
really-unable-to-deserialize-json-into-a-generic-type
感谢所有的答复。
以上是 Spring MVC @RequestBody接收具有非原始属性的对象包装 的全部内容, 来源链接: utcz.com/qa/410212.html