如何在HttpPost中使用参数
我正在通过此方法使用RESTfull Web服务:
@POST@Consumes({"application/json"})
@Path("create/")
public void create(String str1, String str2){
System.out.println("value 1 = " + str1);
System.out.println("value 2 = " + str2);
}
在我的Android应用中,我想调用此方法。如何使用org.apache.http.client.methods.HttpPost给参数赋予正确的值;
我注意到我可以使用批注@HeaderParam并将标题添加到HttpPost对象。这是正确的方法吗?这样做:
httpPost.setHeader("Accept", "application/json");httpPost.setHeader("str1", "a value");
httpPost.setHeader("str2", "another value");
在httpPost上使用setEntity方法将不起作用。它仅使用json字符串设置参数str1。像这样使用时:
JSONObject json = new JSONObject();json.put("str1", "a value");
json.put("str2", "another value");
HttpEntity e = new StringEntity(json.toString());
httpPost.setEntity(e);
//server output: value 1 = {"str1":"a value","str2":"another value"}
回答:
要为您设置参数,HttpPostRequest
可以使用BasicNameValuePair
,例如:
HttpClient httpclient; HttpPost httpPost;
ArrayList<NameValuePair> postParameters;
httpclient = new DefaultHttpClient();
httpPost = new HttpPost("your login link");
postParameters = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("param1", "param1_value"));
postParameters.add(new BasicNameValuePair("param2", "param2_value"));
httpPost.setEntity(new UrlEncodedFormEntity(postParameters, "UTF-8"));
HttpResponse response = httpclient.execute(httpPost);
以上是 如何在HttpPost中使用参数 的全部内容, 来源链接: utcz.com/qa/409820.html