将curl调用转换为java urlconnection调用

  • Z时代
  • 2024-01-10
  • 分类：问答

我有curl命令：

curl -i -u guest:guest -H "content-type:application/json"
-XPUT \ http://localhost:15672/api/traces/%2f/my-trace \
-d'{"format":"text","pattern":"#"}'

我想在Java

API中创建HTTP请求，该操作将执行相同的操作。可以在本README中找到该curl命令。它用于开始在RabbitMQ上记录日志。回应并不重要。

现在，我创建了这样的内容（我删除了不太重要的行，例如捕获了异常等），但是不幸的是，它不起作用：

url = new URL("http://localhost:15672/api/traces/%2f/my-trace");
uc = url.openConnection();
uc.setRequestProperty("Content-Type", "application/json");
uc.setRequestProperty("format","json");
uc.setRequestProperty("pattern","#")
String userpass = "guest:guest";
String basicAuth = "Basic " + javax.xml.bind.DatatypeConverter.printBase64Binary(userpass.getBytes());
uc.setRequestProperty ("Authorization", basicAuth);

完整代码

回答：

这是最终的解决方案：

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.Proxy;
import java.net.InetSocketAddress;
import java.io.OutputStreamWriter;
public class Curl {
  public static void main(String[] args) {
    try {
    String url = "http://127.0.0.1:15672/api/traces/%2f/trololo";
    URL obj = new URL(url);
    HttpURLConnection conn = (HttpURLConnection) obj.openConnection();
    conn.setRequestProperty("Content-Type", "application/json");
    conn.setDoOutput(true);
    conn.setRequestMethod("PUT");
    String userpass = "user" + ":" + "pass";
    String basicAuth = "Basic " + javax.xml.bind.DatatypeConverter.printBase64Binary(userpass.getBytes("UTF-8"));
    conn.setRequestProperty ("Authorization", basicAuth);
    String data =  "{\"format\":\"json\",\"pattern\":\"#\"}";
    OutputStreamWriter out = new OutputStreamWriter(conn.getOutputStream());
    out.write(data);
    out.close();
    new InputStreamReader(conn.getInputStream());
    } catch (Exception e) {
    e.printStackTrace();
    }
  }
}

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