一旦UTF-8编码,如何截断java字符串以适合给定的字节数?
我如何截断一个Java,String
以便我知道一旦它以UTF-8编码,它将适合给定数量的字节存储?
回答:
这是一个简单的循环,用于计算UTF-8表示形式的大小,并在超出时截断:
public static String truncateWhenUTF8(String s, int maxBytes) { int b = 0;
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
// ranges from http://en.wikipedia.org/wiki/UTF-8
int skip = 0;
int more;
if (c <= 0x007f) {
more = 1;
}
else if (c <= 0x07FF) {
more = 2;
} else if (c <= 0xd7ff) {
more = 3;
} else if (c <= 0xDFFF) {
// surrogate area, consume next char as well
more = 4;
skip = 1;
} else {
more = 3;
}
if (b + more > maxBytes) {
return s.substring(0, i);
}
b += more;
i += skip;
}
return s;
}
这 确实可以
处理出现在输入字符串中的代理对。Java的UTF-8编码器(正确)将代理对输出为单个4字节序列而不是两个3字节序列,因此truncateWhenUTF8()
将返回最长的截断字符串。如果您在实现中忽略代理对,则截短的字符串可能会短于所需的长度。
我没有对该代码做很多测试,但是这里有一些初步测试:
private static void test(String s, int maxBytes, int expectedBytes) { String result = truncateWhenUTF8(s, maxBytes);
byte[] utf8 = result.getBytes(Charset.forName("UTF-8"));
if (utf8.length > maxBytes) {
System.out.println("BAD: our truncation of " + s + " was too big");
}
if (utf8.length != expectedBytes) {
System.out.println("BAD: expected " + expectedBytes + " got " + utf8.length);
}
System.out.println(s + " truncated to " + result);
}
public static void main(String[] args) {
test("abcd", 0, 0);
test("abcd", 1, 1);
test("abcd", 2, 2);
test("abcd", 3, 3);
test("abcd", 4, 4);
test("abcd", 5, 4);
test("a\u0080b", 0, 0);
test("a\u0080b", 1, 1);
test("a\u0080b", 2, 1);
test("a\u0080b", 3, 3);
test("a\u0080b", 4, 4);
test("a\u0080b", 5, 4);
test("a\u0800b", 0, 0);
test("a\u0800b", 1, 1);
test("a\u0800b", 2, 1);
test("a\u0800b", 3, 1);
test("a\u0800b", 4, 4);
test("a\u0800b", 5, 5);
test("a\u0800b", 6, 5);
// surrogate pairs
test("\uD834\uDD1E", 0, 0);
test("\uD834\uDD1E", 1, 0);
test("\uD834\uDD1E", 2, 0);
test("\uD834\uDD1E", 3, 0);
test("\uD834\uDD1E", 4, 4);
test("\uD834\uDD1E", 5, 4);
}
修改后的代码示例,现在可以处理代理对。
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