如何解析JSON对象Android Studio

  • Z时代
  • 2024-01-10
  • 分类：问答

JSON对象

{"Title":"Batman Returns","Year":"1992","Rated":"PG-13","Released":"19 Jun 1992","Runtime":"126 min","Genre":"Action","Director":"Tim Burton","Writer":"Bob Kane (Batman characters), Daniel Waters (story), Sam Hamm (story), Daniel Waters (screenplay)","Actors":"Michael Keaton, Danny DeVito, Michelle Pfeiffer, Christopher Walken","Language":"English","Country":"USA, UK","Awards":"Nominated for 2 Oscars. Another 2 wins & 15 nominations.","Poster":"http://ia.media-imdb.com/images/M/MV5BODM2OTc0Njg2OF5BMl5BanBnXkFtZTgwMDA4NjQxMTE@._V1_SX300.jpg","Metascore":"N/A","imdbRating":"7.0","imdbVotes":"199,878","imdbID":"tt0103776","Type":"movie","Response":"True"}

我正在尝试在android studio中解析此对象，但是即时通讯收到错误：

of type org.json.JSONObject cannot be converted to JSONArray

这是我正在使用的代码

JSONArray mJsonArray = new JSONArray(jsonResult);
JSONObject movieObject = mJsonArray.getJSONObject(0);
String title = movieObject.getString("Title");

回答：

您的json包含一个对象，而不是数组。更换

JSONArray mJsonArray = new JSONArray(jsonResult);

通过

JSONObject movieObject = new JSONObject(jsonResult);    
String title = movieObject.getString("Title");

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