Spring Security OAuth2接受JSON

• Z时代
• 2024-01-10
• 分类：问答

我从Spring OAuth2开始。我想将用户名和密码以application / json格式发送到POST正文中的/ oauth / token端点。

curl -X POST -H "Authorization: Basic YWNtZTphY21lc2VjcmV0" -H "Content-Type: application/json" -d '{
"username": "user",
"password": "password",
"grant_type": "password"
}' "http://localhost:9999/api/oauth/token"

那可能吗？

你能给我个建议吗？

回答：

解决方案（不确定是否正确，但表明它正在工作）：

资源服务器配置：

@Configuration
public class ServerEndpointsConfiguration extends ResourceServerConfigurerAdapter {
    @Autowired
    JsonToUrlEncodedAuthenticationFilter jsonFilter;
    @Override
    public void configure(HttpSecurity http) throws Exception {
        http
            .addFilterBefore(jsonFilter, ChannelProcessingFilter.class)
            .csrf().and().httpBasic().disable()
            .authorizeRequests()
            .antMatchers("/test").permitAll()
            .antMatchers("/secured").authenticated();
    }
}

过滤：

@Component
@Order(value = Integer.MIN_VALUE)
public class JsonToUrlEncodedAuthenticationFilter implements Filter {
    @Override
    public void init(FilterConfig filterConfig) throws ServletException {
    }
    @Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException,
            ServletException {
        if (Objects.equals(request.getContentType(), "application/json") && Objects.equals(((RequestFacade) request).getServletPath(), "/oauth/token")) {
            InputStream is = request.getInputStream();
            ByteArrayOutputStream buffer = new ByteArrayOutputStream();
            int nRead;
            byte[] data = new byte[16384];
            while ((nRead = is.read(data, 0, data.length)) != -1) {
                buffer.write(data, 0, nRead);
            }
            buffer.flush();
            byte[] json = buffer.toByteArray();
            HashMap<String, String> result = new ObjectMapper().readValue(json, HashMap.class);
            HashMap<String, String[]> r = new HashMap<>();
            for (String key : result.keySet()) {
                String[] val = new String[1];
                val[0] = result.get(key);
                r.put(key, val);
            }
            String[] val = new String[1];
            val[0] = ((RequestFacade) request).getMethod();
            r.put("_method", val);
            HttpServletRequest s = new MyServletRequestWrapper(((HttpServletRequest) request), r);
            chain.doFilter(s, response);
        } else {
            chain.doFilter(request, response);
        }
    }
    @Override
    public void destroy() {
    }
}

请求包装器：

public class MyServletRequestWrapper extends HttpServletRequestWrapper {
    private final HashMap<String, String[]> params;
    public MyServletRequestWrapper(HttpServletRequest request, HashMap<String, String[]> params) {
        super(request);
        this.params = params;
    }
    @Override
    public String getParameter(String name) {
        if (this.params.containsKey(name)) {
            return this.params.get(name)[0];
        }
        return "";
    }
    @Override
    public Map<String, String[]> getParameterMap() {
        return this.params;
    }
    @Override
    public Enumeration<String> getParameterNames() {
        return new Enumerator<>(params.keySet());
    }
    @Override
    public String[] getParameterValues(String name) {
        return params.get(name);
    }
}

授权服务器配置（对/ oauth / token端点禁用基本身份验证：

    @Configuration
public class AuthorizationServerConfiguration extends AuthorizationServerConfigurerAdapter {
    ...
    @Override
    public void configure(AuthorizationServerSecurityConfigurer oauthServer) throws Exception {
        oauthServer.allowFormAuthenticationForClients(); // Disable /oauth/token Http Basic Auth
    }
    ...
}

以上是 Spring Security OAuth2接受JSON 的全部内容， 来源链接： utcz.com/qa/406207.html