Spring SearchQuery ElasticSearch的每次点击得分
在通过SearchQuery进行搜索时,我试图查看和使用每个匹配项的_score。除了别的以外,这还可以知道我的搜索在哪个分数范围内。但是除了使用searchQuery.withMinScore(float)设置MinScore之外;我找不到任何方法来处理搜索分数。
@Overridepublic Page<Website> listsearch(SearchBody searchBody, int size, int page) {
BoolQueryBuilder qb = QueryBuilders.boolQuery();
for(SearchUnit unit:searchBody.getSearchBody()){
if(unit.isPriority()) {
qb.must(matchQuery("_all", unit.getWord()).operator(MatchQueryBuilder.Operator.AND)
.fuzziness(Fuzziness.AUTO));
}else {
qb.should(termQuery("_all", unit.getWord())
.boost(unit.getWeight()));
}
}
for(SearchUnit ExUnit:searchBody.getExcludeBody()){
qb.mustNot(matchPhraseQuery("_all",ExUnit.getWord()));
}
SearchQuery searchQuery = new NativeSearchQueryBuilder()
.withIndices("websites_v1")
.withTypes("website")
.withQuery(qb)
.withMinScore(0.05F)//Magical minscore
.withPageable(new PageRequest(page, size))
.build();
Page<Website> search = searchRepository.search(searchQuery);
return search;
}
使用的搜索功能来自org.springframework.data.elasticsearch.repository; 定义为
Page<T> search(SearchQuery var1);
所以我的问题是无论如何我都可以访问页面中每个返回对象的分数?还是我需要将查询方法切换到其他方法才能实现?
回答:
使用Spring Data ElasticSearch存储库是不可能的。
您需要自动连接an EntityMapper
和an ElasticSearchTemplate
并自己提取分数。这样的事情应该起作用:
Pageable pageRequest = new PageRequest(0, 10);Page<Website> result = elasticSearchTemplate.query(searchQuery, new ResultsExtractor<Page<Website>>() {
@Override
public Page<Website> extract(SearchResponse response) {
List<Website> content = new ArrayList<>();
SearchHit[] hits = response.getHits().getHits();
for (SearchHit hit : hits) {
Website website = entityMapper.mapToObject(hit, Website.class);
content.add(website);
float documentScore = hit.getScore(); // <---- score of a hit
}
return new PageImpl<Website>(content, pageRequest, response.getHits().getTotalHits());
}
});
以上是 Spring SearchQuery ElasticSearch的每次点击得分 的全部内容, 来源链接: utcz.com/qa/406019.html