计算java中的日期/时间差

• Z时代
• 2024-01-10
• 分类：问答

我想以小时/分钟/秒为单位计算两个日期之间的差异。

我的代码在这里有一个小问题：

String dateStart = "11/03/14 09:29:58";
String dateStop = "11/03/14 09:33:43";
// Custom date format
SimpleDateFormat format = new SimpleDateFormat("yy/MM/dd HH:mm:ss");  
Date d1 = null;
Date d2 = null;
try {
    d1 = format.parse(dateStart);
    d2 = format.parse(dateStop);
} catch (ParseException e) {
    e.printStackTrace();
}    
// Get msec from each, and subtract.
long diff = d2.getTime() - d1.getTime();
long diffSeconds = diff / 1000;         
long diffMinutes = diff / (60 * 1000);         
long diffHours = diff / (60 * 60 * 1000);                      
System.out.println("Time in seconds: " + diffSeconds + " seconds.");         
System.out.println("Time in minutes: " + diffMinutes + " minutes.");         
System.out.println("Time in hours: " + diffHours + " hours."); 

这应该产生：

Time in seconds: 45 seconds.
Time in minutes: 3 minutes.
Time in hours: 0 hours.

但是我得到这个结果：

Time in seconds: 225 seconds.
Time in minutes: 3 minutes.
Time in hours: 0 hours.

有人可以在这里看到我在做什么错吗？

回答：

尝试

long diffSeconds = diff / 1000 % 60;  
long diffMinutes = diff / (60 * 1000) % 60; 
long diffHours = diff / (60 * 60 * 1000);

注意：这假定diff是非负数。

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