具有分页功能的Spring JPA存储库中的自定义查询
我尝试用Spring Boot" title="Spring Boot">Spring Boot实施JPA信息库,效果很好。现在,如果我尝试在使用@Query
Annotation扩展JpaRepository的接口中实现自定义查询,则可以很好地返回bean列表(使用NamedQuery)。现在,当我尝试对自定义方法/查询使用分页时,它不起作用。
代码:
控制器:
@RequestMapping("/custompages/{pageNumber}")public String getAllEmployeesUsingNamedQueryWithPaging(@PathVariable Integer pageNumber,Model model)
{
Page<Employee> page = employeeService.getAllEmployeesUsingNamedQueryWithPaging(pageNumber);
System.out.println("current page "+page);
System.out.println("current page content"+page.getContent());
int current = page.getNumber() + 1;
int begin = Math.max(1, current - 5);
int end = Math.min(begin + 10, page.getTotalPages());
model.addAttribute("empList", page.getContent());
model.addAttribute("empPages", page);
model.addAttribute("beginIndex", begin);
model.addAttribute("endIndex", end);
model.addAttribute("currentIndex", current);
return "employeeWorkbench";
}
服务
@Overridepublic Page<Employee> getAllEmployeesUsingNamedQueryWithPaging(Integer
pageNumber) {
PageRequest pageRequest =
new PageRequest(pageNumber - 1, PAGE_SIZE,
Sort.Direction.ASC, "id");
return
employeeDao.getAllEmployeesUsingNamedQueryWithPaging(pageRequest);
}
道
@Transactionalpublic interface EmployeeDao extends JpaRepository<Employee, Long>{
@Query(name="HQL_GET_ALL_EMPLOYEE_BY_ID")//Works Fine
public List<Employee> getEmpByIdUsingNamedQuery(@Param("empId") Long
empId);
@Query(name="HQL_GET_ALL_EMPLOYEE") //throws exception
public Page<Employee> getAllEmployeesUsingNamedQueryWithPaging(Pageable
pageable);
}
命名查询
<?xml version="1.0"?><!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD
3.0//EN"
"http://hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<query name="HQL_GET_ALL_EMPLOYEE">from Employee</query>
<query name="HQL_GET_ALL_EMPLOYEE_BY_ID">from Employee where id =
:empId</query>
</hibernate-mapping>
异常:java.lang.IllegalArgumentException:为TypedQuery
[java.lang.Long]指定的类型与查询返回类型[class
com.mobicule.SpringBootJPADemo.beans.Employee]不兼容
我只想拥有Spring JPA存储库提供的用于自定义方法和查询的分页功能。我该如何实现?
回答:
我不确定为什么,但是由于某种原因,简单地from Entity
导致返回“ id”,而是需要提供select中返回的实体,例如select f from
Foo f
public interface FooRepo extends PagingAndSortingRepository<Foo, Long> {@Query( "select f from Foo f" )
Page<Foo> findAllCustom( Pageable pageable );
Page<Foo> findAllByBarBazContaining( String baz, Pageable pageable );
}
我收到了同样的错误,只是from
Foo。我也相信您可以像以前一样通过名称将其引用到xml文件。这是我的完整代码
进一步的测试表明它from Foo f
也可行,我不知道为什么需要别名,也许它是JPQL规范的一部分。
这是一个测试,显示如何进行简单的分页,按一个属性排序和按多个属性排序
@Testpublic void testFindAllCustom() throws Exception {
Page<Foo> allCustom = fooRepo.findAllCustom( pageable );
assertThat( allCustom.getSize(), is( 2 ) );
Page<Foo> sortByBazAsc = fooRepo.findAllCustom( new PageRequest( 0, 2, Sort.Direction.ASC, "bar.baz" ) );
assertThat( sortByBazAsc.iterator().next().getBar().getBaz(), is( "2baz2bfoo" ) );
Page<Foo> complexSort = fooRepo.findAllCustom( new PageRequest( 0, 2, new Sort(
new Sort.Order( Sort.Direction.DESC, "bar.baz" ),
new Sort.Order( Sort.Direction.ASC, "id" )
) ) );
assertThat( complexSort.iterator().next().getBar().getBaz(), is( "baz1" ) );
}
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