从Struts2的JSON处理中排除属性
我有以下(完整)实体类。
public class StateTable implements Serializable { private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Basic(optional = false)
@Column(name = "state_id", nullable = false)
private Long stateId;
@Column(name = "state_name", length = 45)
private String stateName;
@OneToMany(mappedBy = "stateId", fetch = FetchType.LAZY)
private Set<UserTable> userTableSet;
@OneToMany(mappedBy = "stateId", fetch = FetchType.LAZY)
private Set<City> citySet;
@OneToMany(mappedBy = "stateId", fetch = FetchType.LAZY)
private Set<Inquiry> inquirySet;
@OneToMany(mappedBy = "shippingState", fetch = FetchType.LAZY)
private Set<OrderTable> orderTableSet;
@OneToMany(mappedBy = "paymentState", fetch = FetchType.LAZY)
private Set<OrderTable> orderTableSet1;
@JoinColumn(name = "country_id", referencedColumnName = "country_id")
@ManyToOne(fetch = FetchType.LAZY)
private Country countryId;
public StateTable() {
}
public StateTable(Long stateId) {
this.stateId = stateId;
}
public Long getStateId() {
return stateId;
}
public void setStateId(Long stateId) {
this.stateId = stateId;
}
public String getStateName() {
return stateName;
}
public void setStateName(String stateName) {
this.stateName = stateName;
}
@XmlTransient
public Set<UserTable> getUserTableSet() {
return userTableSet;
}
public void setUserTableSet(Set<UserTable> userTableSet) {
this.userTableSet = userTableSet;
}
@XmlTransient
public Set<City> getCitySet() {
return citySet;
}
public void setCitySet(Set<City> citySet) {
this.citySet = citySet;
}
@XmlTransient
public Set<Inquiry> getInquirySet() {
return inquirySet;
}
public void setInquirySet(Set<Inquiry> inquirySet) {
this.inquirySet = inquirySet;
}
@XmlTransient
public Set<OrderTable> getOrderTableSet() {
return orderTableSet;
}
public void setOrderTableSet(Set<OrderTable> orderTableSet) {
this.orderTableSet = orderTableSet;
}
@XmlTransient
public Set<OrderTable> getOrderTableSet1() {
return orderTableSet1;
}
public void setOrderTableSet1(Set<OrderTable> orderTableSet1) {
this.orderTableSet1 = orderTableSet1;
}
public Country getCountryId() {
return countryId;
}
public void setCountryId(Country countryId) {
this.countryId = countryId;
}
@Override
public int hashCode() {
int hash = 0;
hash += (stateId != null ? stateId.hashCode() : 0);
return hash;
}
@Override
public boolean equals(Object object) {
// TODO: Warning - this method won't work in the case the id fields are not set
if (!(object instanceof StateTable)) {
return false;
}
StateTable other = (StateTable) object;
if ((this.stateId == null && other.stateId != null) || (this.stateId != null && !this.stateId.equals(other.stateId))) {
return false;
}
return true;
}
@Override
public String toString() {
return "model.StateTable[ stateId=" + stateId + " ]";
}
}
我仅需要此类中的两个属性作为JSON响应,即stateId
和stateName
。其余属性必须被JSON处理/序列化时忽略。
我尝试json.excludeProperties
将json
拦截器设置如下。
@Namespace("/admin_side")@ResultPath("/WEB-INF/content")
@ParentPackage(value="json-default")
public final class StateListAction extends ActionSupport implements Serializable, ValidationAware
{
@Autowired
private final transient SharableService sharableService=null;
private static final long serialVersionUID = 1L;
private Long id;
List<StateTable>stateTables=new ArrayList<StateTable>();
public StateListAction() {}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
@JSON(name="stateTables")
public List<StateTable> getStateTables() {
return stateTables;
}
public void setStateTables(List<StateTable> stateTables) {
this.stateTables = stateTables;
}
@Action(value = "PopulateStateList",
results = {
@Result(type="json", name=ActionSupport.SUCCESS, params={"json.enableSMD", "true", "json.enableGZIP", "true", "json.excludeNullProperties", "true", "json.root", "stateTables", "json.excludeProperties", "userTableSet, citySet, inquirySet, orderTableSet, orderTableSet1, countryId", "validation.validateAnnotatedMethodOnly", "true"})})
public String populateStateList() throws Exception
{
System.out.println("countryId = "+id);
stateTables=sharableService.findStatesByCountryId(id);
return ActionSupport.SUCCESS;
}
}
完成此操作后,其余属性预计将被忽略,但似乎不起作用。生成了与所有实体类相关联的SQL语句的数量,这又导致发生其他严重错误,例如,
org.apache.struts2.json.JSONException: java.lang.IllegalAccessException: Class org.apache.struts2.json.JSONWriter can not access a member of class
org.joda.time.tz.DateTimeZoneBuilder$PrecalculatedZone with modifiers "public"
我在这里想念什么?如何忽略除stateId
和以外的所有属性stateName
?
我正在使用Struts2-json-plugin-2.3.16。
回答:
您需要includeProperties
在json结果中进行配置。例如
@Result(type="json", params = {"contentType", "text/javascript", "includeProperties", "stateTables\\[\\d+\\]\\.stateId,stateTables\\[\\d+\\]\\.stateName"})
以上是 从Struts2的JSON处理中排除属性 的全部内容, 来源链接: utcz.com/qa/403808.html