AWS Java SDK-无法通过区域提供者链找到区域
我经历了题为“以编程方式将AWS区域设置为1”的问题,但它没有提供我需要的所有答案。
Q1:我得到一个SDKClientException-Unable to find a region via the region provider
chain。我究竟做错了什么?还是我错过了错别字。
public class CreateS3Bucket {public static void main(String[] args) throws IOException {
BasicAWSCredentials creds = new BasicAWSCredentials("aws-access-key", "aws-secret-key");
AmazonS3 s3Client = AmazonS3ClientBuilder.standard().withCredentials(new AWSStaticCredentialsProvider(creds)).build();
Region region = Region.getRegion(Regions.US_EAST_1);
s3Client.setRegion(region);
try {
String bucketName = "testBucket" + UUID.randomUUID();
s3Client.createBucket(bucketName);
System.out.println("Bucket Created Successfully.");
} catch(AmazonServiceException awse) {
System.out.println("This means that your request made it AWS S3 but got rejected");
System.out.println("Error Message:" +awse.getMessage());
System.out.println("Error Message:" +awse.getErrorCode());
System.out.println("Error Message:" +awse.getErrorType());
System.out.println("Error Message:" +awse.getRequestId());
} catch (AmazonClientException ace) {
System.out.println("The Amazon Client encountered an Error with network Connectivity");
System.out.println("Error Message:" + ace.getMessage());
}
}
}
问题2:如果要从中构建Lambda函数,需要进行哪些代码更改?我知道如何创建lambda函数及其所需的角色。只是需要知道我编写的代码是否需要更改。我应该如何实现LambdaFuctionHandler类,如下所示:
import com.amazonaws.services.lambda.runtime.Context;import com.amazonaws.services.lambda.runtime.RequestHandler;
public class LambdaFunctionHandler implements RequestHandler<String, String> {
@Override
public String handleRequest(String input, Context context) {
context.getLogger().log("Input: " + input);
return null;
}
}
回答:
关于Q1,请尝试使用以下语法构建客户端:
AmazonS3 amazonS3 = AmazonS3Client.builder() .withRegion("us-east-1")
.withCredentials(new AWSStaticCredentialsProvider(creds))
.build();
以上是 AWS Java SDK-无法通过区域提供者链找到区域 的全部内容, 来源链接: utcz.com/qa/402681.html