如何从python的字典中选择深度嵌套的key:values
我已经从网站下载了json数据,我想从嵌套的json中选择特定的key:values。我将json转换为python字典。然后,我使用字典理解来选择嵌套的key:values,但是嵌套太多了,我相信有比单独扩展每个字典更好的方法。我在我的方法中看到了冗余。您能建议一个更好的方法吗?
{ "success": true,
"payload": {
"tag": {
"slug": "python",
"name": "Python",
"postCount": 10590,
"virtuals": {
"isFollowing": false
}
},
"metadata": {
"followerCount": 18053,
"postCount": 10590,
"coverImage": {
"id": "1*O3-jbieSsxcQFkrTLp-1zw.gif",
"originalWidth": 550,
"originalHeight": 300
}
}
}
}
我的方法:
从datetime导入datetime,timedelta
import json,redata=r'data.json'
#reads json and converts to dictionary
def js_r(data):
with open(data, encoding='Latin-1') as f_in:
return json.load(f_in)
def find_key(obj, key):
if isinstance(obj, dict):
yield from iter_dict(obj, key, [])
elif isinstance(obj, list):
yield from iter_list(obj, key, [])
def iter_dict(d, key, indices):
for k, v in d.items():
if k == key:
yield indices + [k], v
if isinstance(v, dict):
yield from iter_dict(v, key, indices + [k])
elif isinstance(v, list):
yield from iter_list(v, key, indices + [k])
def iter_list(seq, key, indices):
for k, v in enumerate(seq):
if isinstance(v, dict):
yield from iter_dict(v, key, indices + [k])
elif isinstance(v, list):
yield from iter_list(v, key, indices + [k])
if __name__=="__main__":
my_dict=js_r(data)
print ( "This is dictionary for python tag",my_dict)
keys=my_dict.keys()
print ("This is the dictionary keys",my_dict.keys())
my_payload=list(find_key(my_dict,'title'))
print ("These are my payload",my_payload)
my_post=iter_dict(my_dict,'User','id')
print(list(my_post))
回答:
我建议您使用python-benedict
,具有完整的 和许多实用程序方法的可靠python dict子类。
它提供多种格式的IO支持,包括json
。
您可以直接从json
文件初始化它:
from benedict import benedictd = benedict.from_json('data.json')
现在您的字典具有关键路径支持:
print(d['payload.metadata.coverImage.id'])# or use get to avoid a possible KeyError
print(d.get('payload.metadata.coverImage.id'))
安装: pip install python-benedict
这里是库存储库和文档:https :
//github.com/fabiocaccamo/python-
benedict
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