如何使用dom parser java解析xml中的同名标签？

  • Z时代
  • 2024-01-10
  • 分类：问答

如何使用dom parser java在xml中解析相同的名称标签？

我有以下要使用Java中的dom解析器解析的xml文件。

<?xml version="1.0"?>
    <GameWorld>
        <player>
            <playerID>1</playerID>
            <inventory>
                <item>cards</item>
                <item>notes</item>
                <item>dice</item>
            </inventory>
            <position>50 50 10 60</position>
            <room>offices</room>
        </player>
        <player>
            <playerID>2</playerID>
            <inventory>
                <item>notes</item>
                <item>dice</item>
                <item>cards</item>
            </inventory>
            <position>10 10 10</position>
            <room>security room</room>
        </player>
    </GameWorld>

回答：

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(f);
Element root = doc.getDocumentElement();
NodeList nodeList = doc.getElementsByTagName("player");
for (int i = 0; i < nodeList.getLength(); i++) {
  Node node = nodeList.item(i);
  // do your stuff
}

但我建议使用XPath

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse(<uri_as_string>);
XPathFactory xPathfactory = XPathFactory.newInstance();
XPath xpath = xPathfactory.newXPath();
XPathExpression expr = xpath.compile("/GameWorld/player");
NodeList nl = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);

以上是 如何使用dom parser java解析xml中的同名标签？ 的全部内容， 来源链接： utcz.com/qa/400829.html

回到顶部