用Javascript排序JSON对象

  • Z时代
  • 2024-01-10
  • 分类：问答

我一直在寻找排序这样的JSON对象的时间

{"results": [
  {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "35",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "SADD MAARAB PHARMACY",
      },
    "geometryType": "esriGeometryPoint",
   },
  {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "1",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "GAYATHY HOSPITAL  PHARMACY",
    },
    "geometryType": "esriGeometryPoint",
  },
     {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "255",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "AL DEWAN PHARMACY",
      },
    "geometryType": "esriGeometryPoint",
   }
]}

按字母顺序按“ COMMERCIALNAME_E”的值获取

{"results": [
   {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "255",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "AL DEWAN PHARMACY",
      },
    "geometryType": "esriGeometryPoint",
   },
  {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "1",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "GAYATHY HOSPITAL  PHARMACY",
       },
    "geometryType": "esriGeometryPoint",
   },
   {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "35",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "SADD MAARAB PHARMACY",
      },
    "geometryType": "esriGeometryPoint",
   }
]}

我找不到任何可以做到这一点的代码。谁能给我些帮助吗？

回答：

function sortJsonArrayByProperty(objArray, prop, direction){
    if (arguments.length<2) throw new Error("sortJsonArrayByProp requires 2 arguments");
    var direct = arguments.length>2 ? arguments[2] : 1; //Default to ascending
    if (objArray && objArray.constructor===Array){
        var propPath = (prop.constructor===Array) ? prop : prop.split(".");
        objArray.sort(function(a,b){
            for (var p in propPath){
                if (a[propPath[p]] && b[propPath[p]]){
                    a = a[propPath[p]];
                    b = b[propPath[p]];
                }
            }
            // convert numeric strings to integers
            a = a.match(/^\d+$/) ? +a : a;
            b = b.match(/^\d+$/) ? +b : b;
            return ( (a < b) ? -1*direct : ((a > b) ? 1*direct : 0) );
        });
    }
}
sortJsonArrayByProperty(results, 'attributes.OBJECTID');
sortJsonArrayByProperty(results, 'attributes.OBJECTID', -1);

更新：请勿更改

function sortByProperty(objArray, prop, direction){
    if (arguments.length<2) throw new Error("ARRAY, AND OBJECT PROPERTY MINIMUM ARGUMENTS, OPTIONAL DIRECTION");
    if (!Array.isArray(objArray)) throw new Error("FIRST ARGUMENT NOT AN ARRAY");
    const clone = objArray.slice(0);
    const direct = arguments.length>2 ? arguments[2] : 1; //Default to ascending
    const propPath = (prop.constructor===Array) ? prop : prop.split(".");
    clone.sort(function(a,b){
        for (let p in propPath){
                if (a[propPath[p]] && b[propPath[p]]){
                    a = a[propPath[p]];
                    b = b[propPath[p]];
                }
        }
        // convert numeric strings to integers
        a = a.match(/^\d+$/) ? +a : a;
        b = b.match(/^\d+$/) ? +b : b;
        return ( (a < b) ? -1*direct : ((a > b) ? 1*direct : 0) );
    });
    return clone;
}
const resultsByObjectId = sortByProperty(results, 'attributes.OBJECTID');
const resultsByObjectIdDescending = sortByProperty(results, 'attributes.OBJECTID', -1);

以上是 用Javascript排序JSON对象 的全部内容， 来源链接： utcz.com/qa/400262.html

回到顶部