PHP电子邮件表单发送者名称而不是电子邮件?

现在,我已经建立了一个PHP电子邮件表单,并且一切正常。但是,在测试时,我只得到了发件人的电子邮件地址作为名称。我想要的是发件人的姓名,例如:

约翰·杜

科目科目科目

代替:

j.doe@website.com

科目科目科目

下面是代码…

有谁可以帮助我吗?谢谢。

PHP:

<?php

if(isset($_POST['email'])) {

// EDIT THE 2 LINES BELOW AS REQUIRED

$email_to = "ricky@rickytsang.ca";

$email_subject = $_REQUEST['subject'];

function died($error) {

// your error code can go here

echo "We are very sorry, but there were error(s) found with the form you submitted. ";

echo "These errors appear below.<br /><br />";

echo $error."<br /><br />";

echo "Please go back and fix these errors.<br /><br />";

die();

}

// validation expected data exists

if(!isset($_POST['full_name']) ||

!isset($_POST['email']) ||

!isset($_POST['subject']) ||

!isset($_POST['message'])) {

died('We are sorry, but there appears to be a problem with the form you submitted.');

}

$full_name = $_POST['full_name']; // required

$email_from = $_POST['email']; // required

$subject = $_POST['subject'];

$message= $_POST['message']; // required

$error_message = "";

$email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';

if(!preg_match($email_exp,$email_from)) {

$error_message .= 'The e-mail you entered does not appear to be valid.<br />';

}

$string_exp = "/^[A-Za-z .'-]+$/";

if(!preg_match($string_exp,$full_name)) {

$error_message .= 'The name you entered does not appear to be valid.<br />';

}

if(strlen($message) < 2) {

$error_message .= 'The message you entered doee not appear to be valid.<br />';

}

if(strlen($error_message) > 0) {

died($error_message);

}

$email_message = "Form details below.\n\n";

function clean_string($string) {

$bad = array("content-type","bcc:","to:","cc:","href");

return str_replace($bad,"",$string);

}

$email_message .= "Full Name: ".clean_string($full_name)."\n";

$email_message .= "E-mail: ".clean_string($email_from)."\n";

$email_message .= "Subject: ".clean_string($subject)."\n";

$email_message .= "Message: ".clean_string($message)."\n";

// create email headers

$headers = 'From: '.$email_from."\r\n".

'Reply-To: '.$email_from."\r\n" .

'X-Mailer: PHP/' . phpversion();

@mail($email_to, $email_subject, $email_message, $headers);

?>

<!-- include your own success html here -->

Thank you for contacting us. We will be in touch with you very soon.

<?php

}

?>

回答:

在您的4行说完之后$email_message .= ...添加一行:

$email_from = $full_name.'<'.$email_from.'>';

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