Spring Boot服务注入到doFiler

  • Z时代
  • 2024-01-10
  • 分类：问答

我正在尝试将身份验证服务注入Filter-

@Autowired
AuthRequestService authService;

并在doFiler方法中使用它-

@Override
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain)
        throws IOException, ServletException {
    HttpServletRequest req = (HttpServletRequest) request;
    System.out.println("SAPServiceFilter: "+ req.getRequestURI());
    //TODO - create auth sender
    authService.isAuthnticate((HttpServletRequest)request); //null
    chain.doFilter(request, response);
}

我的过滤器类位于类的子包中，@SpringBoot" title="SpringBoot">SpringBootApplication并带有@service-

@Service
public class AuthRequestService {
    @PostConstruct
    public void init() {
        System.out.println("AuthRequestService @PostConstruct");
    }
    public boolean isAuthnticate(HttpServletRequest request) {
        System.out.println("isAuthnticate");
        return true;
    }
}

当使用-列出我的所有豆子时，该类也会出现

for (String name : applicationContext.getBeanDefinitionNames()) {
    System.out.println(name);
}

仍然当调试authService为null时，向过滤器注册的最后一件事FilterRegistrationBean-

FilterRegistrationBean<SAPServiceFilter> filterRegBean = new FilterRegistrationBean<>();
filterRegBean.setFilter(new SAPServiceFilter());

回答：

您可以使用构造函数注入。假设您的过滤器注册Bean位于组件中，并且可以访问该服务，您可以在其中自动进行连接并将其传递给构造函数

@Autowired  
AuthRequestService authRequestService;
[...]
FilterRegistrationBean<SAPServiceFilter> filterRegBean = new FilterRegistrationBean<>();
filterRegBean.setFilter(new SAPServiceFilter(authRequestService));

以上是 Spring Boot服务注入到doFiler 的全部内容， 来源链接： utcz.com/qa/399640.html

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