将异常从CXF拦截器传播到异常映射器
我有一个流程,在CXF客户端上我安装了拦截器,提供程序和异常映射程序。就我而言,我正在通过拦截器捕获来自客户端的不良响应,然后我想中止cxf总线链并引发故障。不幸的是我做不到,因为在每种情况下都只记录从拦截器抛出的异常,但是主要错误(错误的json格式)会传播到异常映射器。我想避免使用异常映射器,但是我不知道怎么做。我正在使用WebClient来实现这样的拦截器:
@Componentpublic class MyInterceptor extends AbstractPhaseInterceptor<Message> {
public MyInterceptor() {
super(POST_STREAM);
}
@Override
public void handleMessage(Message message) throws Fault {
if (message != null) {
//message.getExchange().setOneWay(true);
//message.getExchange().put(Exception.class, new MyException());
//message.getInterceptorChain().abort();
//message.setContent(Exception.class, new MyException());
//Endpoint ep = message.getExchange().get(Endpoint.class);
//message.getInterceptorChain().abort();
//if (ep.getInFaultObserver() != null) {
// ep.getInFaultObserver().onMessage(message);
//}
//throw new WebApplicationException( new MyException());
//message.setContent(Response.class, response);
throw new Fault(new MyException());
}
}
我读到我应该实现jaxrs-filter,因为拦截器引发的异常不会传播到异常映射器。多亏了WebClient的实现,在Java中有没有办法做到这一点?
S client = create(url, clazz, list(jsonProvider(), providers));WebClient.getConfig(client).getInInterceptors().add(new MyInterceptor());
我也尝试过在拦截器上使用不同的阶段,但是也没有用。
回答:
我一直在研究和测试您的问题。问题是从CXF拦截器抛出的异常逃避了JAX-
RS流(请参阅
CXF团队的答案)
甲Fault
从拦截器产生可以被获取,实现handleFault
在拦截器本身
public void handleFault(Message message) { Exception e = message.getContent(Exception.class);
}
或实施FaultListener
并在CXF总线上注册
WebClient.getConfig(client).getBus().getProperties().put("org.apache.cxf.logging.FaultListener",new MyFaultListener());public class MyFaultListener implements FaultListener{
public boolean faultOccurred(final Exception exception,final String description,final Message message) {
//return false to avoid warning of default CXF logging interceptor
return false;
}
}
我发现实现所需行为的解决方法是将Response替换为可以由您的常规方法调用处理的自定义对象
进入Interceptor.handleMessage
检查你所需要的条件,并创建一个Response
自定义状态和实体。之后,停止链条
public class MyInterceptor extends AbstractPhaseInterceptor<Message> { public MyInterceptor() {
super(Phase.POST_STREAM);
}
@Override
public void handleMessage(Message message) throws Fault {
if (message != null) {
//check the condition to raise the error
//build the custom Response replacing service call
Response response = Response
.status(Response.Status.BAD_REQUEST)
.entity("custom error")
.build();
message.getExchange().put(Response.class, response);
//abort interceptor chain in you want to stop processing or throw a Fault (catched by handleFault)
//message.getInterceptorChain().abort();
//throw new Fault (new MyException());
}
public void handleFault(Message messageParam) {
}
}
创建JAXRS客户端时,将ResponseExceptionMapper添加为提供者
providers.add(new ResponseExceptionMapper<WebApplicationException>() { @Override
public WebApplicationException fromResponse(Response r) {
return new WebApplicationException(r);
}
});
YourService proxy = JAXRSClientFactory.create(url, clazz,providers);
Client client = WebClient.client(proxy);
WebClient.getConfig(client).getInInterceptors().add(new MyInterceptor());
此后,对的调用proxy.yourService()
将引发WebApplicationException
if如果完成拦截器检查。您可以按期望的方式抓住它或将其扔掉
try{ proxy.yourService();
}catch (WebApplicationException e){
}
希望这可以帮助
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