如何为复杂的json文档定义avro模式?
我有一个想要转换为Avro的JSON文档,并且需要为此指定一种模式。这是我要为其定义avro模式的JSON文档:
{ "uid": 29153333,
"somefield": "somevalue",
"options": [
{
"item1_lvl2": "a",
"item2_lvl2": [
{
"item1_lvl3": "x1",
"item2_lvl3": "y1"
},
{
"item1_lvl3": "x2",
"item2_lvl3": "y2"
}
]
}
]
}
我可以为非复杂类型定义架构,但不能为复杂的“选项”字段定义架构:
{ "namespace" : "my.com.ns",
"type" : "record",
"fields" : [
{"name": "uid", "type": "int"},
{"name": "somefield", "type": "string"}
{"name": "options", "type": .....}
]
}
谢谢您的帮助!
回答:
您需要使用Avro
复杂类型,尤其是数组和记录。然后将它们嵌套在一起:
{ "namespace" : "my.com.ns",
"name": "myrecord",
"type" : "record",
"fields" : [
{"name": "uid", "type": "int"},
{"name": "somefield", "type": "string"},
{"name": "options", "type": {
"type": "array",
"items": {
"type": "record",
"name": "lvl2_record",
"fields": [
{"name": "item1_lvl2", "type": "string"},
{"name": "item2_lvl2", "type": {
"type": "array",
"items": {
"type": "record",
"name": "lvl3_record",
"fields": [
{"name": "item1_lvl3", "type": "string"},
{"name": "item2_lvl3", "type": "string"}
]
}
}}
]
}
}}
]
}
另外,为了提高可读性,您可以将架构分为多个文件。
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