如何使用Java将文件从Zip文件读取到内存中?
我从SUN网站(http://java.sun.com/developer/technicalArticles/Programming/compression/)找到了示例,但是它返回BufferedOutputStream。但是我想将ZipEntry文件作为InputStream,然后处理下一个文件。那可能吗?我的程序无法访问硬盘,因此它甚至无法临时保存文件。
import java.io.*;import java.util.zip.*;
public class UnZip {
final int BUFFER = 2048;
public static void main (String argv[]) {
try {
BufferedOutputStream dest = null;
FileInputStream fis = new
FileInputStream(argv[0]);
ZipInputStream zis = new
ZipInputStream(new BufferedInputStream(fis));
ZipEntry entry;
while((entry = zis.getNextEntry()) != null) {
System.out.println("Extracting: " +entry);
int count;
byte data[] = new byte[BUFFER];
// write the files to the disk
FileOutputStream fos = new
FileOutputStream(entry.getName());
dest = new
BufferedOutputStream(fos, BUFFER);
while ((count = zis.read(data, 0, BUFFER))
!= -1) {
dest.write(data, 0, count);
}
dest.flush();
dest.close();
}
zis.close();
} catch(Exception e) {
e.printStackTrace();
}
}
}
回答:
好吧,只需将将文件写入文件的部分更改为您要处理的数据即可。
while((entry = zis.getNextEntry()) != null) { System.out.println("Extracting: " + entry);
int count;
byte[] data = new byte[BUFFER];
String filename = entry.getName();
System.out.println("Filename: " + filename);
while ((count = zis.read(data, 0, BUFFER)) != -1) {
// Do whatever you want with the data variable
System.out.println(data);
}
}
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