如何从数组返回值到函数

Z时代
2024-01-10
分类：问答

这里我计算两个纬度和经度点之间的距离和时间。几乎我得到了答案，但我无法将该值返回给该函数。如何从数组返回值到函数

请帮帮我。在此先感谢

我的编码是：

function initMap() { 
     console.log(getDistanceandTime(srcRouteAddress.lat,srcRouteAddress.lng,destRouteAddress.lat,destRouteAddress.lng)); 
     function getDistanceandTime(lat1,lon1,lat2,lon2){ 
     var origin = {lat: parseFloat(lat1), lng: parseFloat(lon1)}; 
     var destination = {lat: parseFloat(lat2), lng: parseFloat(lon2)}; 
     var service = new google.maps.DistanceMatrixService; 
     //var test = []; 
     service.getDistanceMatrix({ 
      origins: [origin], 
      destinations: [destination], 
      travelMode: google.maps.TravelMode.DRIVING 
     }, function (response, status) { 
      if (status == google.maps.DistanceMatrixStatus.OK) { 
       var test_values = []; 
       var originList = response.originAddresses; 
       for (var i = 0; i < originList.length; i++) { 
        var results = response.rows[i].elements; 
        for (var j = 0; j < results.length; j++) { 
         var test = results[j].distance.text + ' in ' + results[j].duration.text; 
         test_values.push(test); 
         console.log(test_values); 
        } 
       } 
       return test_values; 
      } 
      return test_values; 
     }); 
    } 
    }

回答：

，如果它是一个同步调用，那就试试这个，你var test_values = [];外应if (status == google.maps.DistanceMatrixStatus.OK)条件。而最有可能的内部if (status == google.maps.DistanceMatrixStatus.OK)不执行

也google.maps.DistanceMatrixStatus.OK是异步的更好的内部if(google.maps.DistanceMatrixStatus.OK)

返回值，以便尝试这种

function initMap() { 
    console.log(getDistanceandTime(srcRouteAddress.lat,srcRouteAddress.lng,destRouteAddress.lat,destRouteAddress.lng)); 
    function getDistanceandTime(lat1,lon1,lat2,lon2){ 
    var origin = {lat: parseFloat(lat1), lng: parseFloat(lon1)}; 
    var destination = {lat: parseFloat(lat2), lng: parseFloat(lon2)}; 
    var service = new google.maps.DistanceMatrixService; 
    //var test = []; 
    service.getDistanceMatrix({ 
     origins: [origin], 
     destinations: [destination], 
     travelMode: google.maps.TravelMode.DRIVING 
    }, function (response, status) { 
         var test_values = []; 
     if (status == google.maps.DistanceMatrixStatus.OK) { 
      var originList = response.originAddresses; 
      for (var i = 0; i < originList.length; i++) { 
       var results = response.rows[i].elements; 
       for (var j = 0; j < results.length; j++) { 
        var test = results[j].distance.text + ' in ' + results[j].duration.text; 
        test_values.push(test); 
        console.log(test_values); 
       } 
      } 
      return test_values; 
     } 
    }); 
    } 
}

回答：

试试这个..

var test_values = []; // global variable 
function initMap() { 
    // your code here 
} 
function showLatLng(){ 
    console.log(test_values); // will output the content 
}