C＃在Windows窗体应用程序中实时绘图

Z时代
2024-01-10
分类：问答

我试图绘制使用Modbus命令读取的实时温度。目前，我可以读取温度并绘制图表。但是，一旦绘制出第一点，它就不会持续更新图形和GUI。C＃在Windows窗体应用程序中实时绘图

我应该在Form1_Load以外的方法中运行这个吗？

private void Form1_Load(object sender, EventArgs e) 
{ 
    chart1.ChartAreas.Add("Area"); 
    chart1.ChartAreas["Area"].AxisX.Minimum = -100; 
    chart1.ChartAreas["Area"].AxisX.Maximum = 100; 
    chart1.ChartAreas["Area"].AxisX.Interval = 1; 
    chart1.ChartAreas["Area"].AxisY.Minimum = -100; 
    chart1.ChartAreas["Area"].AxisY.Maximum = 100; 
    chart1.ChartAreas["Area"].AxisY.Interval = 1; 
    //create a Data object array 
    val[] data = new val[5]; 
    string[] ports = SerialPort.GetPortNames(); 
    this.comboBox1.DataSource = ports; 
    serialPort1.PortName = "COM5"; 
    using (SerialPort port = new SerialPort("COM5")) 
    { 
     //start time object 
     DateTime start = DateTime.Now; 
     int startSec = start.Second; 
     port.Open(); 
     byte slaveID = 1; 
     ushort startAddress = 360; 
     ushort numOfPoints = 2; 
     ModbusSerialMaster master = ModbusSerialMaster.CreateRtu(port); 
     for (int j = 0; j < 5; j++) 
     { 
      ushort[] holding_register = master.ReadHoldingRegisters(slaveID, startAddress, 
      numOfPoints); 
      ushort val1 = holding_register[0]; 
      ushort val2 = holding_register[1]; 
      uint t1 = (uint)(holding_register[0]); 
      uint t2 = (uint)(holding_register[1] << 16); 
      uint temp = (uint)(t1) | (t2); 
      byte[] floatVals = BitConverter.GetBytes(temp); 
      float f = BitConverter.ToSingle(floatVals, 0); 
      c = 5.0/9.0 * (f - 32); 
      textBox1.Text = c.ToString(); 
      DateTime current = DateTime.Now; 
      int currentSec = current.Second; 
      int time = currentSec - startSec; 
      chart1.Refresh(); 
      data[j].time = time; 
      data[j].temperature = c; 
      chart1.Series[j].Points.Add(new DataPoint(data[j].time, data[j].temperature)); 
      chart1.Refresh(); 
      port.Close(); 
     } 
    } 
}