路由返回无效的JSON。也许是一个例外抛出？
我一直在努力将JWT authentication添加到我的Lumen API中。请记住我是流明，API设计和TDD的新手。在添加认证之前，所有的测试都通过了。老实说，除了我运行phpunit时，一切看起来都很好。难以理解的是，当我在postman中运行相同的测试时，我没有任何问题，但是当我在phpunit中转储响应时，我得到了NULL。也许一组新的眼睛可以帮助我？路由返回无效的JSON。也许是一个例外抛出？
我已经添加了jwt.auth中间件到我的限制路线：
routes.php文件我的控制器的
// all other code omitted $app->group([
'prefix' => $version . '/authors',
'middleware' => 'jwt.auth',
'namespace' => 'App\Http\Controllers',
], function ($app) {
$app->get('/{id:[\d]+}', ['as' => 'authors.show', 'uses' => '[email protected]']);
});
部分如下：
AuthorsController.php
class AuthorsController extends Controller {
// all other code omitted
public function show($id)
{
return $this->item(Author::findOrFail($id), new AuthorTransformer());
}
}
我的模型如下
Author.php
class Author extends Model {
/**
* The attributes that are mass assignable
*
* @var array
*/
protected $fillable = ['name', 'biography', 'gender'];
public function books()
{
return $this->hasMany(Book::class);
}
}
我的变压器如下：
AuthorTransformer.php
class AuthorTransformer extends TransformerAbstract {
protected $availableIncludes = [
'books',
];
public function includeBooks(Author $author)
{
return $this->collection($author->books, new BookTransformer());
}
/**
* Transform an author model
*
* @param Author $author
* @return array
*/
public function transform(Author $author)
{
return [
'id' => $author->id,
'name' => $author->name,
'gender' => $author->gender,
'biography' => $author->biography,
'created' => $author->created_at->toIso8601String(),
'updated' => $author->created_at->toIso8601String(),
];
}
}
而我的测试是如下：
TestCase.php
class TestCase extends Laravel\Lumen\Testing\TestCase {
// all other code omitted
/**
* Convenience method for creating a user
*
* @return $user
*/
protected function userFactory()
{
$user = factory(\App\User::class, 1)->create(['password' => app('hash')->make('supersecret')]);
return $user;
}
/**
* Convenience method for getting jwt and authenticating
*
* @return $body
*/
protected function jwtAuthTest($method, $url, $body = [])
{
$user = $this->userFactory();
$token = JWTAuth::fromUser($user);
JWTAuth::setToken($token);
$headers = array(
"Accept" => "application/json",
"Authorization" => "Bearer " . $token,
);
switch ($method) {
case 'get':
$this->get($url, $body, $headers);
break;
case 'post':
$this->post($url, $body, $headers);
break;
case 'put':
$this->put($url, $body, $headers);
break;
case 'patch':
$this->patch($url, $body, $headers);
break;
case 'delete':
$this->delete($url, $body, $headers);
break;
}
$data = json_decode($this->response->getContent(), true);
return $data;
}
}
AuthorsControllerTest.php
class AuthorsControllerTest extends TestCase {
// all other code omitted
/** @test **/
public function show_should_fail_on_an_invalid_author()
{
$body = $this->jwtAuthTest('get', '/v1/authors/1234');
// this works fine...
$this->seeStatusCode(Response::HTTP_NOT_FOUND);
// NULL??
var_dump($body);
}
}
我的回答应该是：
{ "error": {
"message": "Not Found",
"status": 404
}
}
但是我得到NULL
当我测试与邮差有效令牌我得到的，这就是我期待在我的测试中，我同样的路线：
{ "error": {
"message": "Not Found",
"status": 404
}
}
突然我的路线返回在PHPUnit测试空。我似乎无法弄清楚为什么？
我的处理程序如下：
// all other code omitted class Handler extends ExceptionHandler
{
/**
* A list of the exception types that should not be reported.
*
* @var array
*/
protected $dontReport = [
AuthorizationException::class,
HttpException::class,
ModelNotFoundException::class,
ValidationException::class,
];
/**
* Report or log an exception.
*
* This is a great spot to send exceptions to Sentry, Bugsnag, etc.
*
* @param \Exception $e
* @return void
*/
public function report(Exception $e)
{
parent::report($e);
}
/**
* Render an exception into an HTTP response.
*
* @param \Illuminate\Http\Request $request
* @param \Exception $e
* @return \Illuminate\Http\Response
*/
public function render($request, Exception $e)
{
if ($request->wantsJson()) {
$response = [
'message' => (string) $e->getMessage(),
'status' => 400,
];
if ($e instanceof HttpException) {
$response['message'] = Response::$statusTexts[$e->getStatusCode()];
$response['status'] = $e->getStatusCode();
} else if ($e instanceof ModelNotFoundException) {
$response['message'] = Response::$statusTexts[Response::HTTP_NOT_FOUND];
$response['status'] = Response::HTTP_NOT_FOUND;
}
if ($this->isDebugMode()) {
$response['debug'] = [
'exception' => get_class($e),
'trace' => $e->getTrace(),
];
}
return response()->json(['error' => $response], $response['status']);
}
return parent::render($request, $e);
}
}
当我的测试失败，我得到：
There was 1 failure: 1) Tests\App\Http\Controllers\AuthorsControllerTest::show_should_fail_on_an_invalid_author
Invalid JSON was returned from the route. Perhaps an exception was thrown?
请让我知道，如果你有什么事，并预先感谢您。
的源代码：https://github.com/studio174/gscp
回答：
的问题是在TestCase.php有一个简单的命名冲突和无效使用get（）方法的：
TestCase.php
/** * Convenience method for getting jwt and authenticating
*
* @return $body
*/
protected function jwtAuthTest($method, $url, $body = [])
{
$user = $this->userFactory();
$token = JWTAuth::fromUser($user);
JWTAuth::setToken($token);
$headers = array(
"Accept" => "application/json",
"Authorization" => "Bearer " . $token,
);
switch ($method) {
case 'get':
// [FIX] removed $body from get request as this was overwriting my headers
// and causing my handler to return plain text instead of JSON
$this->get($url, $headers);
break;
case 'post':
$this->post($url, $body, $headers);
break;
case 'put':
$this->put($url, $body, $headers);
break;
case 'patch':
$this->patch($url, $body, $headers);
break;
case 'delete':
$this->delete($url, $body, $headers);
break;
}
// [FIX] changed $body= json_decode($this->response->getContent(), true);
$data = json_decode($this->response->getContent(), true);
return $data;
}
以上是 路由返回无效的JSON。也许是一个例外抛出？ 的全部内容， 来源链接： utcz.com/qa/266812.html
