Python重构此功能以将其认知复杂度从19降低到15允许
我从sonarlint看到此消息并试图找出如何减少此功能的认知复杂性。任何援助提前赞赏。Python重构此功能以将其认知复杂度从19降低到15允许
import os import json
import click
import hcl
cfn = [".json", ".template", ".yaml", ".yml"]
tf = ["tf"]
def file_handler(dir):
for root, dirs, files in os.walk(dir):
for file in files:
if file.endswith(tuple(cfn)):
with open(os.path.join(root, file), 'r') as fin:
try:
file = fin.read()
if "AWSTemplateFormatVersion" in file:
data = json.dumps(file)
print(data)
except ValueError as e:
raise SystemExit(e)
elif file.endswith(tuple(tf)):
with open(os.path.join(root, file), 'r') as file:
try:
obj = hcl.load(file)
data = json.dumps(obj)
print(data)
except ValueError as e:
raise SystemExit(e)
return data
回答:
取出功能产生的文件路径:
def _file_paths(directory): for root, dirs, filenames in os.walk(directory):
for filename in filenames:
file_path = os.path.join(root, filename)
if os.path.isfile(file_path):
yield file_path
统一的异常处理:
from contextlib import contextmanager @contextmanager
def _translate_error(from_error, to_error):
try:
yield
except from_error as error:
raise to_error(error)
提取函数来处理文件类型:
def _handle_cfn(file_object): file_contents = file_object.read()
if "AWSTemplateFormatVersion" in file_contents:
data = json.dumps(file_contents)
print(data)
def _handle_tf(file_object):
obj = hcl.load(file_oject)
data = json.dumps(obj)
print(data)
创建时的文件空处理程序扩展名不符:
def _null_handler(file_object): pass
个 地图文件扩展名的处理程序:
_extension_handlers = {'.json': _handle_cfn, '.template': _handle_cfn,
'.yaml': _handle_cfn,
'.yml': _handle_cfn,
'.tf': _handle_tf}
将其组合在一起:
def _handle_file(file_path): base, extension = os.path.splitext(file_path)
handler = _extension_handlers.get(extension, _null_handler)
with open(file_path) as file_object:
with _translate_error(ValueError, SystemExit):
handler(file_object)
然后:
import os import json
import click
import hcl
def file_handler(dir):
for file_path in _file_paths(dir):
base, extension = os.path.splitext(file_path)
handler = _extension_handlers.get(extension, _null_handler)
with open(file_path) as file_object:
with _translate_error(ValueError, SystemExit):
handler(file_object)
您可以通过处理每个文件中提取出功能走得更远您的主要功能是:
def file_handler(dir): for file_path in _file_paths(dir):
_handle_file(file_path)
回答:
您可以通过使用两个发电机表达式通过扩展过滤文件中删除缩进一层:
def file_handler(dir): for root, dirs, files in os.walk(dir):
cfn_files = (file for file in files if file.endswith(tuple(cfn)))
tf_files = (file for file in files if file.endswith(tuple(tf)))
for file in cfn_files:
with open(os.path.join(root, file), 'r') as fin:
try:
file = fin.read()
if "AWSTemplateFormatVersion" in file:
data = json.dumps(file)
print(data)
except ValueError as e:
raise SystemExit(e)
for file in tf_files:
with open(os.path.join(root, file), 'r') as file:
try:
obj = hcl.load(file)
data = json.dumps(obj)
print(data)
except ValueError as e:
raise SystemExit(e)
return data
回答:
当你知道你应该考虑使用glob
递归文件中查找尤其是哪些文件扩展名你是在寻找:
import glob import json
import os
import click
import hcl
def file_handler(dir):
for extension in cfn:
# eg: /path/to/dir/**/*.json
glob_search = os.path.join(dir, "**/*{}".format(extension))
filenames = glob.glob(glob_search, recursive=True)
for filename in filenames:
with open(filename, 'r') as fin:
try:
file = fin.read()
if "AWSTemplateFormatVersion" in file:
data = json.dumps(file)
print(data)
except ValueError as e:
raise SystemExit(e)
for extension in tf:
# eg: /path/to/dir/**/*tf
glob_search = os.path.join(dir, "**/*{}".format(extension))
filenames = glob.glob(glob_search, recursive=True)
for filename in filenames:
with open(filename, 'r') as file:
try:
obj = hcl.load(file)
data = json.dumps(obj)
print(data)
except ValueError as e:
raise SystemExit(e)
FYI:关于使用水珠的一个问题(Use a Glob() to find files recursively in Python?)
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