Java线程等待值

  • Z时代
  • 2024-01-10
  • 分类：问答

我有以下情况：Java线程等待值

为了运行一个算法，我必须运行多个线程和每个线程都设置一个实例变量x，它死前。问题是这些线程不会立即返回：

public Foo myAlgorithm() 
{ 
    //create n Runnables (n is big) 
    //start these runnables (may take long time do die) 
    //i need the x value of each runnable here, but they havent finished yet! 
    //get average x from all the runnables 
    return new Foo(averageX); 
}

我应该使用等待通知吗？或者我应该只是嵌入一个while循环并检查终止？

谢谢大家！

回答：

创建一些共享存储来保存来自每个线程的值x，或者只需存储总和即可。使用CountDownLatch等待线程终止。每个线程完成后将调用CountDownLatch.countDown()，并且您的myAlgorithm方法将使用CountDownLatch.await()方法等待它们。

编辑：下面是我建议的方法的完整示例。它创建了39个工作线程，每个线程都将一个随机数添加到共享总和中。当所有工人都完成后，平均数就会被计算和打印。

import java.util.Random; 
import java.util.concurrent.CountDownLatch; 
import java.util.concurrent.atomic.AtomicInteger; 
class Worker implements Runnable { 
    private final AtomicInteger sum; 
    private final CountDownLatch latch; 
    public Worker(AtomicInteger sum, CountDownLatch latch) { 
     this.sum = sum; 
     this.latch = latch; 
    } 
    @Override 
    public void run() { 
     Random random = new Random(); 
     try { 
      // Sleep a random length of time from 5-10s 
      Thread.sleep(random.nextInt(5000) + 5000); 
     } catch (InterruptedException e) { 
      e.printStackTrace(); 
     } 
     // Compute x 
     int x = random.nextInt(500); 
     // Add to the shared sum 
     System.out.println("Adding " + x + " to sum"); 
     sum.addAndGet(x); 
     // This runnable is finished, so count down 
     latch.countDown(); 
    } 
} 
class Program { 
    public static void main(String[] args) { 
     // There will be 39 workers 
     final int N = 39; 
     // Holds the sum of all results from all workers 
     AtomicInteger sum = new AtomicInteger(); 
     // Tracks how many workers are still working 
     CountDownLatch latch = new CountDownLatch(N); 
     System.out.println("Starting " + N + " workers"); 
     for (int i = 0; i < N; i++) { 
      // Each worker uses the shared atomic sum and countdown latch. 
      Worker worker = new Worker(sum, latch); 
      // Start the worker 
      new Thread(worker).start(); 
     } 
     try { 
      // Important: waits for all workers to finish. 
      latch.await(); 
     } catch (InterruptedException e) { 
      e.printStackTrace(); 
     } 
     // Compute the average 
     double average = (double) sum.get()/(double) N; 
     System.out.println(" Sum: " + sum.get()); 
     System.out.println("Workers: " + N); 
     System.out.println("Average: " + average); 
    } 
}

输出应该是这样的：

Starting 39 workers 
Adding 94 to sum 
Adding 86 to sum 
Adding 454 to sum 
... 
... 
... 
Adding 358 to sum 
Adding 134 to sum 
Adding 482 to sum 
    Sum: 10133 
Workers: 39 
Average: 259.8205128205128

编辑：只是为了好玩，这里是一个使用ExecutorService，Callable和Future一个例子。

import java.util.ArrayList; 
import java.util.Collection; 
import java.util.List; 
import java.util.Random; 
import java.util.concurrent.Callable; 
import java.util.concurrent.ExecutionException; 
import java.util.concurrent.ExecutorService; 
import java.util.concurrent.Future; 
import java.util.concurrent.ScheduledThreadPoolExecutor; 
class Worker implements Callable<Integer> { 
    @Override 
    public Integer call() throws Exception { 
     Random random = new Random(); 
     // Sleep a random length of time, from 5-10s 
     Thread.sleep(random.nextInt(5000) + 5000); 
     // Compute x 
     int x = random.nextInt(500); 
     System.out.println("Computed " + x); 
     return x; 
    } 
} 
public class Program { 
    public static void main(String[] args) { 
     // Thread pool size 
     final int POOL_SIZE = 10; 
     // There will be 39 workers 
     final int N = 39; 
     System.out.println("Starting " + N + " workers"); 
     // Create the workers 
     Collection<Callable<Integer>> workers = new ArrayList<Callable<Integer>>(N); 
     for (int i = 0; i < N; i++) { 
      workers.add(new Worker()); 
     } 
     // Create the executor service 
     ExecutorService executor = new ScheduledThreadPoolExecutor(POOL_SIZE); 
     // Execute all the workers, wait for the results 
     List<Future<Integer>> results = null; 
     try { 
      // Executes all tasks and waits for them to finish 
      results = executor.invokeAll(workers); 
     } catch (InterruptedException e) { 
      e.printStackTrace(); 
      return; 
     } 
     // Compute the sum from the results 
     int sum = 0; 
     for (Future<Integer> future : results) { 
      try { 
       sum += future.get(); 
      } catch (InterruptedException e) { 
       e.printStackTrace(); return; 
      } catch (ExecutionException e) { 
       e.printStackTrace(); return; 
      } 
     } 
     // Compute the average 
     double average = (double) sum/(double) N; 
     System.out.println("   Sum: " + sum); 
     System.out.println("  Workers: " + N); 
     System.out.println("  Average: " + average); 
    } 
}

输出应该是这样的：

Starting 39 workers 
Computed 419 
Computed 36 
Computed 338 
... 
... 
... 
Computed 261 
Computed 354 
Computed 112 
     Sum: 9526 
    Workers: 39 
    Average: 244.25641025641025

回答：

您可以让以及所有相关的东西，如ThreadPools，Executors等知道。Teaser：A Future是一个带返回值的线程。

回答：

使用ExecutorService，并提交每个任务（为Callable）将其

，你会得到一个未来提交

每个任务 

List<Future<ResultType>> results = exec.invokeAll(tasks);//tasks is a set of Callable<ResultType> 
//invokeAll blocks untill all tasks are finished 
for(Future<ResultType> f:results){ 
    ResultType x=f.get();//loop over Futures to get the result 
    //do something with x 
}

以上是 Java线程等待值 的全部内容， 来源链接： utcz.com/qa/265912.html

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