使用urllib阅读mashabe API

  • Z时代
  • 2024-01-10
  • 分类：问答

我有这段代码来阅读python 2中的Mashape.com API。我如何在python 3中阅读它？使用urllib阅读mashabe API

代码

import urllib, urllib2, json 
from pprint import pprint 
URL = "https://getsentiment.p.mashape.com/" 
text = "The food was great, but the service was slow." 
params = {'text': text, 'domain': 'retail', 'terms': 1, 'categories': 1,'sentiment': 1, 'annotate': 1} 
headers = {'X-Mashape-Key': YOUR_MASHAPE_KEY} 
opener = urllib2.build_opener(urllib2.HTTPHandler) 
request = urllib2.Request(URL, urllib.urlencode(params), headers=headers) 
response = opener.open(request) 
opener.close() 
data = json.loads(response.read()) 
pprint(data)

我想这代码，但它有以下错误：

import urllib.parse 
import urllib.request 
URL = "https://getsentiment.p.mashape.com/" 
text = "The food was great, but the service was slow." 
params = {'text': text, 'domain': 'retail', 'terms': 1, 'categories': 1, 'sentiment': 1, 'annotate': 1} 
headers = {'X-Mashape-Key': YOUR_MASHAPE_KEY} 
opener = urllib.request.build_opener(urllib.request.HTTPHandler) 
request = urllib.request.Request(URL, urllib.parse.urlencode(params), headers) 
response = opener.open(request) 
opener.close() 
data = json.loads(response.read()) 
print(data)

错误：

TypeError: POST data should be bytes or an iterable of bytes. It cannot be of type str.

回答：

在这一行：

request = urllib.request.Request(URL, urllib.parse.urlencode(params), headers)

尝试更换到

data = urllib.parse.urlencode(params).encode('utf-8') 
request = urllib.request.Request(URL, data, headers)

以上是 使用urllib阅读mashabe API 的全部内容， 来源链接： utcz.com/qa/264470.html

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