上一个/下一个按钮?
我想输入上一个和下一个按钮为我有一个论坛,因为在论坛变长之后,它超过了背景图像,并且看起来不太好!有谁知道要么做一个简单的方法,或者我可以看看上一个和下一个按钮?我想要它,所以每页仅限于每页5个帖子或其他内容。上一个/下一个按钮?
继承人的代码,如果它有所帮助。如果这是一个愚蠢的问题,我很抱歉。
<?php $dbc=mysql_connect('host','user','password','database') or die(mysql_error());
mysql_select_db('database',$dbc) or die(mysql_error());
?>
View Posts <br>
<form method="get" action="view_forum.php">
<label>Select Weather to Filter </label><br />
<select name="weather">
<option value="all">all</option>
<option value="cloudy">Cloudy</option>
<option value="sunny">Sunny</option>
<option value="windy">Windy</option>
<option value="snowy">Snowy</option>
<option value="mixy">Wintery Mix</option>
<option value="rainy">Rainy</option>
</select>
<input type="submit" value="view" />
</form>
<div id="view">
<center><img src="images/forum.png" width="589" height="97"></center>
</div>
<div id="white">
<div id="blue">
<div id="grey">
<div id="container">
<?php
$weather = mysql_real_escape_string($_GET["weather"]); // keep your input clean
if ($weather == "all") {
$sql = "SELECT * FROM stories ORDER BY id DESC";
} else {
$sql = "SELECT * FROM stories WHERE weather = '$weather' ORDER BY id DESC";
}
$result = mysql_query($sql) or die(mysql_error());
while ($row = mysql_fetch_assoc($result)) {
echo "<div class=\"names\"> {$row['name']}<br /></div>";
echo "<div class=\"weathers\">{$row['weather']}<br /></div>";
echo "<div class=\"stories\">{$row['story']}<br /></div>";
echo "<img src=\"images/line.png\" width='800' height='3'>";
echo "<br />";
}
?>
</div>
</div>
</div>
</div>
回答:
很简单。你在请求中保留一个页面变量。
if (!isset($_GET['page']) { $page = 1;
} else {
$page = (int)$_GET['page'];
}
而且在你的SQL语句,你会把这样的事情,它使用的页面变量调整的查询范围:
$query = 'SELECT * FROM someTable WHERE 1 LIMIT ' . (($page - 1) * $recordsPerPage) . ' ' . $recordsPerPage;
类似的东西反正。现在为您上一页和下一页链接你把这样的事情,这样就可以增加/减少页面变量:
<? if ($page > 1) : ?> <a href="self.php?page=<?= $page - 1 ?>">Prev</a>
<? endif ?>
<? if ($page != $maxPages) : ?>
<a href="self.php?page=<?= $page + 1 ?>">Next</a>
<? endif ?>
回答:
您需要分页,在MySQL中,你可以使用TOP:
-- Fist 10 results: SELECT * FROM stories ORDER BY id DESC TOP 10
-- 10 results from the number 11 (0 is the first)
SELECT * FROM stories ORDER BY id DESC TOP 10,10
-- 10 results from the number 50
SELECT * FROM stories ORDER BY id DESC TOP 50,10
对于知道总的结果,你可以使用SQL_CALC_FOUND_ROWS:
SELECT SQL_CALC_FOUND_ROWS as total, stories.* FROM stories ORDER BY id DESC TOP 10
从PHP,你可以计算出分页:
$page = isset($_GET['page']) ? (int) $_GET['page'] : 1; if ($page < 1) $page = 1;
$sql = "SELECT SQL_CALC_FOUND_ROWS as total, stories.* FROM stories ORDER BY id DESC TOP " . ($page-1) . ",10";
以上是 上一个/下一个按钮? 的全部内容, 来源链接: utcz.com/qa/263833.html