如何在python中仅使用Tk快速绘制位图？

未遂3 - 我发誓最后一...

我相信这是最快的纯TK办法做到这一点。在列表列表中生成10,000个RGB值，创建Tkinter.PhotoImage，然后将像素值放入其中。

import Tkinter, random 
class App: 
    def __init__(self, t): 
     self.i = Tkinter.PhotoImage(width=100,height=100) 
     colors = [[random.randint(0,255) for i in range(0,3)] for j in range(0,10000)] 
     row = 0; col = 0 
     for color in colors: 
      self.i.put('#%02x%02x%02x' % tuple(color),(row,col)) 
      col += 1 
      if col == 100: 
       row +=1; col = 0   
     c = Tkinter.Canvas(t, width=100, height=100); c.pack() 
     c.create_image(0, 0, image = self.i, anchor=Tkinter.NW) 
t = Tkinter.Tk() 
a = App(t)  
t.mainloop() 

ATTEMPT 1 - 利用create_rectangle方法

我写这作为测试。在2.67千兆赫我的英特尔酷睿2双核处理器，它会吸取0.6秒，想想5000像素，包括产生随机我RGB值时间：

from Tkinter import * 
import random 
def RGBs(num): 
# random list of list RGBs 
return [[random.randint(0,255) for i in range(0,3)] for j in range(0,num)] 
def rgb2Hex(rgb_tuple): 
    return '#%02x%02x%02x' % tuple(rgb_tuple) 
def drawGrid(w,colors): 
col = 0; row = 0 
colors = [rgb2Hex(color) for color in colors] 
for color in colors: 
    w.create_rectangle(col, row, col+1, row+1, fill=color, outline=color) 
    col+=1 
    if col == 100: 
    row += 1; col = 0 
root = Tk() 
w = Canvas(root) 
w.grid() 
colors = RGBs(5000) 
drawGrid(w,colors) 
root.mainloop() 

未遂2 - 使用PIL

我知道你只说TK，但PIL使这真的很容易和快速。

def rgb2Hex(rgb_tuple): 
    return '#%02x%02x%02x' % tuple(rgb_tuple) 
num = 10000 #10,000 pixels in 100,100 image 
colors = [[random.randint(0,255) for i in range(0,3)] for j in range(0,num)] 
colors = [rgb2Hex(color) for color in colors] 
im = Image.fromstring('RGB',(100,100),"".join(colors)) 
tkpi = ImageTk.PhotoImage(im) 
## add to a label or whatever... 
label_image = Tkinter.Label(root, image=tkpi) 

有一个更快的纯Tkinter的方法：

import Tkinter, random 
import random 
class App: 
    def __init__(self, t): 
     self.width = 320 
     self.height = 200 
     self.i = Tkinter.PhotoImage(width=self.width,height=self.height) 
     rgb_colors = ([random.randint(0,255) for i in range(0,3)] for j in range(0,self.width*self.height)) 
     pixels=" ".join(("{"+" ".join(('#%02x%02x%02x' % 
      tuple(next(rgb_colors)) for i in range(self.width)))+"}" for j in range(self.height))) 
     self.i.put(pixels,(0,0,self.width-1,self.height-1)) 
     c = Tkinter.Canvas(t, width=self.width, height=self.height); c.pack() 
     c.create_image(0, 0, image = self.i, anchor=Tkinter.NW) 
t = Tkinter.Tk() 
a = App(t)  
t.mainloop() 

您可以使用put（）方法来绘制一些颜色数据（一个字符串）创建一个矩形，在这种情况下，整个图像。这样你就不需要很昂贵的循环。