如何通过API将文档上传至watson发现服务。 ASP.net

Z时代
2024-01-10
分类：问答

我正在使用以下API将文件上传到watson发现服务。即使我提供了一个有效的类型，我也会得到不支持的文件格式的响应。 API：discovery service api如何通过API将文档上传至watson发现服务。 ASP.net

public async Task<ActionResult> Index() 
    { 
     using (var httpClient = new HttpClient()) 
     { 
      //ADD BASIC AUTH 
      var authByteArray = Encoding.ASCII.GetBytes("{auth key}"); 
      var authString = Convert.ToBase64String(authByteArray); 
      httpClient.DefaultRequestHeaders.Authorization = new AuthenticationHeaderValue("Basic", authString); 
      var text = string.Empty; 
      var uri = "https://gateway.watsonplatform.net/discovery/api/v1/environments/{envid}/collections/{collectionid}/documents?version=2017-11-07"; 
      var content = new MultipartFormDataContent(); 
      var bytes = System.IO.File.ReadAllBytes(Server.MapPath("~/Views/UploadDocument/civilwar-api1.html")); 
      var file = new StreamContent(new MemoryStream(bytes)); 
      content.Headers.ContentType = MediaTypeHeaderValue.Parse("text/html"); 
      content.Add(new StreamContent(new MemoryStream(bytes)), "file"); 
      var response = await httpClient.PostAsync(uri, content); 
      var text1 = await response.Content.ReadAsStringAsync(); 
     } 
     return View(); 
    }

API响应为：{ "code" : 415, "error" : "Unsupported Media Type" }

回答：

尝试httpClient.DefaultRequestHeaders .Accept .Add(new MediaTypeWithQualityHeaderValue("application/json"));//ACCEPT header

回答：

正如你可以看到沃森开发者云，你可以使用.NET SDK。

在此存储库中，您可以看到使用Watson的每项服务的examples。

的方法来添加一个文件：

#region Documents 
     private void AddDocument() 
     { 
      Console.WriteLine(string.Format("\nCalling AddDocument()...")); 
      using (FileStream fs = File.OpenRead(_filepathToIngest)) 
      { 
       var result = _discovery.AddDocument(_createdEnvironmentId, _createdCollectionId, _createdConfigurationId, fs as Stream, _metadata); 
       if (result != null) 
       { 
        Console.WriteLine(JsonConvert.SerializeObject(result, Formatting.Indented)); 
        _createdDocumentId = result.DocumentId; 
       } 
       else 
       { 
        Console.WriteLine("result is null."); 
       } 
      } 
     }